關(guān)于normalize函數(shù)record[i,:] != 0
record[i,:] != 0這個(gè)能獲取!=0的列下標(biāo)嗎，大家也偶人試了沒(méi)，我這不行的
qq_三斤_0
2020-02-07
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2020-02-07
#?我改成了這樣可以運(yùn)行 for?i?in?range(m): ????#獲取一部電影評(píng)分用戶(hù)的id ????ids?=?np.nonzero(record[i])[0] ????#ids?=?record[i,:]?!=?0? ????rating_mean[i]?=?np.mean(rating[i,ids]) ????#rating_norm[i,ids]?-=?rating_mean[i] ????rating_norm[i,ids]?=?rating[i,ids]?-?rating_mean[i] ????print("The?row?is?{},mean?rating?is?{},rating?user?size?is?{}" ????.format(i,rating_mean[i],ids.shape))