關(guān)于normalize函數(shù)record[i,:] != 0

record[i,:] != 0這個能獲取!=0的列下標嗎，大家也偶人試了沒，我這不行的

qq_三斤_0

2020-02-07

源自：推薦算法理論與實踐 3-2

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qq_三斤_0 提問者
2020-02-07

#?我改成了這樣可以運行
for?i?in?range(m):
????#獲取一部電影評分用戶的id
????ids?=?np.nonzero(record[i])[0]
????#ids?=?record[i,:]?!=?0?
????rating_mean[i]?=?np.mean(rating[i,ids])
????#rating_norm[i,ids]?-=?rating_mean[i]
????rating_norm[i,ids]?=?rating[i,ids]?-?rating_mean[i]
????print("The?row?is?{},mean?rating?is?{},rating?user?size?is?{}"
????.format(i,rating_mean[i],ids.shape))