2 回答x%y和x%%y

2 回答#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

2 回答include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

3 回答int x=5;    int y=5;    int z=10;    printf("x是否大于y:%d\n",x>y ); //x是否大于y    printf("y是否大于等于x:%d\n", y>=x ); //y是否大于等于x    printf("y是否小于z:%d\n", y<z ); //y是否小于z    printf("z是否小于等于x:%d\n",z<=x ); //z是否小于等于x    printf("z是否等于x+y:%d\n",  z==x+y  ); //z

1 回答 printf("x%%y=%d\n",x%y );與 printf("x%y=%d\n",x%y );