include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

include <stdio.h>

int main()

{

? ? int x,y;

? ? x = 10;

? ? y = -3;

? ? printf("x+y=%d\n", ? x+y ?); ?

? ? printf("x-y=%d\n", ? x-y ?);

? ? printf("x*y=%d\n", ? x*y ?);

? ? printf("x/y=%d\n", ?x/y ? );

? ? printf("x%y=%d\n", ? x%y ?); ?

? ? return 0; ? ?

}

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2015-01-23

源自：C語言入門 3-2

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qq_ShortybCut_0
2017-11-17

?printf("x%%y=%d\n", ? x%y ?); ?

0 回復有任何疑惑可以回復我~

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Perona
2015-12-12

筆記請記筆記區(qū)

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2 回答#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

6 回答#include <stdio.h> int main() { int a,s,d,f,g; a=x+y; s=x-y; d=x*y;f=x/y;g=x%y;printf("x+y=%d\n", a);printf("x-y=%d\n", s);printf("x*y=%d\n", d ); printf("x/y=%d\n", f);printf("x%y=%d\n", g);return 0;}

1 回答 printf("x%%y=%d\n",x%y );與 printf("x%y=%d\n",x%y );

1 回答printf("x%%y=%d\n", x%y );

4 回答printf("x%%y=%d\n",x%y);

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include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

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include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

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include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;