2 回答然而求余得y=%d,而不是x%y=1,問題在哪呢？

1 回答為什么第11行printf("x%%y=%d\n", x%y );后面的那個x%y不用打兩個%

2 回答#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

2 回答include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

1 回答 printf("x%%y=%d\n",x%y );與 printf("x%y=%d\n",x%y );