參考答案j、k在for循環(huán)中都被賦予了初始值 所以把代碼循環(huán)部分的k用j來替代表達應該完全沒問題
2015-03-07
#include <stdio.h>
#define a 97;
int main()
{
char c = 'a';
int n = c; //將c賦值給n
float f = n; //將c賦值給f
double d = f; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
#define a 97;
int main()
{
char c = 'a';
int n = c; //將c賦值給n
float f = n; //將c賦值給f
double d = f; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
2015-03-07
int i, j, k;
for(i=1; i<5; i++)
{
for(j=5;j>i;j--)
{
printf(" ");
}
for( k=1 ; k<i+j ; k++)
{
printf("*");
}
printf("\n");
}
for(i=1; i<5; i++)
{
for(j=5;j>i;j--)
{
printf(" ");
}
for( k=1 ; k<i+j ; k++)
{
printf("*");
}
printf("\n");
}
2015-03-07
if(sale > 100 && year >= 2 ){
printf("%s\n","優(yōu)秀員工");
}else{
printf("%s\n","很遺憾,再接再厲");
}
既然提示錯誤,
printf("%s\n","優(yōu)秀員工");
}else{
printf("%s\n","很遺憾,再接再厲");
}
既然提示錯誤,
2015-03-06
for( num=100;num<1000;num++)
hd = num/100;
td = num/10-hd*10;
sd = num-hd*100-td*10
if( num==hd*hd*hd+td*td*td+sd*sd*sd)
hd = num/100;
td = num/10-hd*10;
sd = num-hd*100-td*10
if( num==hd*hd*hd+td*td*td+sd*sd*sd)
2015-03-06