#include <stdio.h>
int main()
{
int x = 0;
printf("x=%d\n",x++);
printf("x=%d\n",++x);
return 0;
}
我終于搞定了哈哈
int main()
{
int x = 0;
printf("x=%d\n",x++);
printf("x=%d\n",++x);
return 0;
}
我終于搞定了哈哈
2015-01-15
5-6練習(xí)題1/1中
C用戶定義的函數(shù)中如果有return語句,函數(shù)可以為void類型
這個(gè)選項(xiàng)設(shè)定為正確,沒明白正確的原因。請(qǐng)教各位。謝謝。
C用戶定義的函數(shù)中如果有return語句,函數(shù)可以為void類型
這個(gè)選項(xiàng)設(shè)定為正確,沒明白正確的原因。請(qǐng)教各位。謝謝。
2015-01-15
已采納回答 / Fiona0126
這個(gè)啊。。對(duì)于這些規(guī)律性的東西,可以通過觀察或者在紙上寫寫每一行的個(gè)數(shù)有什么特性,萬變不離其宗。對(duì)于提高思維能力,我覺得可以做一些算法的題目~~
2015-01-15
#include <stdio.h>
#define a 97
int main()
{
char c = 'a';
int n = a; //將c賦值給n
float f = a; //將c賦值給f
double d = a; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
根據(jù)上一節(jié)課的內(nèi)容可以這樣寫
#define a 97
int main()
{
char c = 'a';
int n = a; //將c賦值給n
float f = a; //將c賦值給f
double d = a; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
根據(jù)上一節(jié)課的內(nèi)容可以這樣寫
2015-01-15
#include<stdio.h>
int main(){
int x = 10;
int y = -3;
printf("x + y =%d\n",x + y);
printf("x - y =%d\n",x - y);
printf("x * y =%d\n",x * y);
printf("x / y =%d\n",x / y);
printf("x% y =%d\n",x% y);
}
就這樣
int main(){
int x = 10;
int y = -3;
printf("x + y =%d\n",x + y);
printf("x - y =%d\n",x - y);
printf("x * y =%d\n",x * y);
printf("x / y =%d\n",x / y);
printf("x% y =%d\n",x% y);
}
就這樣
2015-01-15
#include<stdio.h>
int main(){
int a,b,c,d,e;
a = 5;
b = 9;
c = 18;
d = a + c;
e = d - b;
printf("%d\n%d\n%d\n%d\n",a + d,c - e,b * a,d - a / e);
//僅僅隨意寫的,不知道為什么double在visula studio 聲稱有問題
}
int main(){
int a,b,c,d,e;
a = 5;
b = 9;
c = 18;
d = a + c;
e = d - b;
printf("%d\n%d\n%d\n%d\n",a + d,c - e,b * a,d - a / e);
//僅僅隨意寫的,不知道為什么double在visula studio 聲稱有問題
}
2015-01-15
#include<stdio.h>
int main(){
double num = 2.4;
int b = (int) num;
printf("num的整數(shù)部分是%d\n",b);
}
就這樣
int main(){
double num = 2.4;
int b = (int) num;
printf("num的整數(shù)部分是%d\n",b);
}
就這樣
2015-01-15
#include<stdio.h>
int main(){
int c = 97;
double z,x;
z = x;
x = c;
printf("%d\n",c);
printf("%f\n",x);
printf("%f\n",z);
}
這樣就ok
int main(){
int c = 97;
double z,x;
z = x;
x = c;
printf("%d\n",c);
printf("%f\n",x);
printf("%f\n",z);
}
這樣就ok
2015-01-15
printf("x=%d\n", x*=2);
printf("y=%d\n", y*=2);
printf("y=%d\n", y*=2);
2015-01-15