討論一下思路:
T = (1, 'CH', [3, 4])
tuple里面包含list,導(dǎo)致tuple是可變的,請修改T的定義,不改變基本數(shù)據(jù)類型的數(shù)據(jù),使T是不可變的。
關(guān)于題干
目的:使其數(shù)據(jù)類型的數(shù)據(jù)不可變
拆分:那些數(shù)據(jù)是可變的?如何變成不可變的?
結(jié)果:列表中3,4是可變的,將其改為元組的形式即可
代碼實現(xiàn):自己來吧。
T = (1, 'CH', [3, 4])
tuple里面包含list,導(dǎo)致tuple是可變的,請修改T的定義,不改變基本數(shù)據(jù)類型的數(shù)據(jù),使T是不可變的。
關(guān)于題干
目的:使其數(shù)據(jù)類型的數(shù)據(jù)不可變
拆分:那些數(shù)據(jù)是可變的?如何變成不可變的?
結(jié)果:列表中3,4是可變的,將其改為元組的形式即可
代碼實現(xiàn):自己來吧。
2021-12-15
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for i in T:
print(i)
3
for i in T:
print(i)
3
2021-12-15
sum = 1
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
2021-12-10
L = [75, 92, 59, 68, 99]
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
2021-12-10
x=(1,5,8,4)
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
2021-12-08
l=[1, 4, 5, 7, 9, 11]
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶數(shù)項和={}'.format(result[0]))
print('奇數(shù)項和={}'.format(result[1]))
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶數(shù)項和={}'.format(result[0]))
print('奇數(shù)項和={}'.format(result[1]))
2021-12-08
abc = 'Life is short,{}'
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
2021-12-08
x=[1,2,5,6,8]
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
2021-12-06
# Enter a code
l=[]
a=0
while a<=100:
l.append(a*a)
a=a+1
print(sum(l))
l=[]
a=0
while a<=100:
l.append(a*a)
a=a+1
print(sum(l))
2021-12-06
# Enter a code
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if s1.isdisjoint(s2) != True:
for a in s1:
if a in s2:
print(a)
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if s1.isdisjoint(s2) != True:
for a in s1:
if a in s2:
print(a)
2021-12-06
a = 0
i = 0
while True:
if a > 1000:
break
if a % 2 == 0:
i = i + a
a = a + 1
print(i)
i = 0
while True:
if a > 1000:
break
if a % 2 == 0:
i = i + a
a = a + 1
print(i)
2021-12-06
a = 1
sun =1
while a <= 10:
sun =sun * a
a = a + 1
print(sun)
sun =1
while a <= 10:
sun =sun * a
a = a + 1
print(sun)
2021-12-06
# Enter a code
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s3=[]
for a in s1:
if a in s2:
s3.append(a)
else:
continue
print(s3)
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s3=[]
for a in s1:
if a in s2:
s3.append(a)
else:
continue
print(s3)
2021-12-06
age = 2
if age >= 18:
print('你是成年人,你{}歲了'.format(age))
print("adult")
elif age >= 6:
print('你是青少年,你{}歲了'.format(age))
print("teenager")
elif age >= 3:
print('你是小孩子,你{}歲了'.format(age))
print("kid")
else:
print('你是嬰兒,你{}歲了'.format(age))
print("baby")
if age >= 18:
print('你是成年人,你{}歲了'.format(age))
print("adult")
elif age >= 6:
print('你是青少年,你{}歲了'.format(age))
print("teenager")
elif age >= 3:
print('你是小孩子,你{}歲了'.format(age))
print("kid")
else:
print('你是嬰兒,你{}歲了'.format(age))
print("baby")
2021-12-05
age = 3
if age >= 18:
print("adult")
elif age >= 6:
print("teenager")
elif age >= 3:
print("kid")
else:
print("baby")
if age >= 18:
print("adult")
elif age >= 6:
print("teenager")
elif age >= 3:
print("kid")
else:
print("baby")
2021-12-05