d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
for key in d:
print(key)
for v in d[key]:
print(v)
print("-------------------")
for key,value in d.items():
print(key)
for vc in value:
print(vc)
for key in d:
print(key)
for v in d[key]:
print(v)
print("-------------------")
for key,value in d.items():
print(key)
for vc in value:
print(vc)
2025-10-14
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
for key in d:
print(key)
print(d[key])
print("-------------------")
for key,value in d.items():
print(key)
print(value)
for key in d:
print(key)
print(d[key])
print("-------------------")
for key,value in d.items():
print(key)
print(value)
2025-10-14
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d)
d['Alice'] = 60
print(d)
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d)
d['Alice'] = 60
print(d)
2025-10-14
L = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
for i in L:
print(i)
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
for i in L:
print(i)
2025-10-12
s1 ='ABC'
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
print(a+b+c)
s2='123'
s3='XYZ'
for a in s1:
for b in s2:
for c in s3:
print(a+b+c)
2025-10-12
a =0
b=0
while a <= 1000:
if a % 2 != 0:
continue
b= b+a
a = a+1
print(b)
b=0
while a <= 1000:
if a % 2 != 0:
continue
b= b+a
a = a+1
print(b)
2025-10-12
a=0
sum=0
while True:
if a % 2 == 0:
sum=sum+a
a=a+1
if a > 1000:
break
print("a:{},sum:{}",a,sum)
sum=0
while True:
if a % 2 == 0:
sum=sum+a
a=a+1
if a > 1000:
break
print("a:{},sum:{}",a,sum)
2025-10-12
L = [75, 92, 59, 68, 99]
sum = 0
for ch in L:
sum = sum + ch
print(sum)
sum = 0
for ch in L:
sum = sum + ch
print(sum)
2025-10-12
a = 3.14
b= 1.57
s = a*b
print(round(s,2));
b= 1.57
s = a*b
print(round(s,2));
2025-10-10
(1+2):計(jì)算結(jié)果為 3(整數(shù),不是元組)
((1+2),):是一個(gè)嵌套元組(內(nèi)部元素是 3),屬于元組
('a'+'b'):計(jì)算結(jié)果為 'ab'(字符串,不是元組)
(1, ):是包含一個(gè)整數(shù)的元組,屬于元組
(1,2,3,4,5):是包含 5 個(gè)整數(shù)的元組,屬于元組
因此,共 3 個(gè)
((1+2),):是一個(gè)嵌套元組(內(nèi)部元素是 3),屬于元組
('a'+'b'):計(jì)算結(jié)果為 'ab'(字符串,不是元組)
(1, ):是包含一個(gè)整數(shù)的元組,屬于元組
(1,2,3,4,5):是包含 5 個(gè)整數(shù)的元組,屬于元組
因此,共 3 個(gè)
2025-09-24
第一次刪除 'Candy'(索引 2)后,列表元素的索引會(huì)自動(dòng)重新排列
原來(lái)的 'David' 的索引從 3 變?yōu)?2,因此第二次需要?jiǎng)h除索引 2 才能正確移除 'David'
最終結(jié)果為 ['Alice', 'Bob', 'Ellena'],符合預(yù)期
原來(lái)的 'David' 的索引從 3 變?yōu)?2,因此第二次需要?jiǎng)h除索引 2 才能正確移除 'David'
最終結(jié)果為 ['Alice', 'Bob', 'Ellena'],符合預(yù)期
2025-09-24