def my_work(**kwargs):
for j , i in enumerate(kwargs.get('names')):
print('姓名:{},性別:{},年齡:{}'.format(i,kwargs.get('gender')[j],kwargs.get('age')[j]))
return
my_work(names=['熊貓','大象','狗熊'],gender=['男','女','男'],age=[18,28,33])
for j , i in enumerate(kwargs.get('names')):
print('姓名:{},性別:{},年齡:{}'.format(i,kwargs.get('gender')[j],kwargs.get('age')[j]))
return
my_work(names=['熊貓','大象','狗熊'],gender=['男','女','男'],age=[18,28,33])
2022-02-11
最新回答 / 慕斯卡8373086
def sums (n):? ? refult = 0? ? if n > 0 and n <= 100:? ? ? ? while n > 0 :? ? ? ? ? ? refult = refult + n? ? ? ? ? ? n -= 1? ? ? ? return refult? ? else:? ? ? ? return '參數(shù)要在1-100之間'n1 = 99print(sums(n1))def fact(n):? ? if n == 1:? ? ? ? return 1?...
2022-02-11
最贊回答 / 慕神7009732
s1 = set([1, 2, 3, 4, 5])s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])s3=set()s4=set()print(s1.isdisjoint(s2))a=Falseif s1.isdisjoint(s2)==a:? ? s3=s2-s1? ? L=list(s3)? ? T=tuple(s3)? ? print(L,T)else:? ? print(s4)a=False 不要帶引號(hào)，帶了引號(hào)是表示字符串，不是布爾類型，所以不成立
2022-02-10
最贊回答 / 慕村3371467
答案說的3個(gè)是“((1+2),)，(1, )，（1,2,3,4,5）”第一跟第三個(gè)是因?yàn)闆]有在tuple里面加逗號(hào)（,），所以不算是tuple。
2022-02-09
def square_of_sum(L):
L1=[]
for i in L:
L1.extend([i*i])
return sum(L1)
print(square_of_sum([1, 2, 3, 4, 5]))
L1=[]
for i in L:
L1.extend([i*i])
return sum(L1)
print(square_of_sum([1, 2, 3, 4, 5]))
2022-02-09
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
new_names=[]
for i in names:
name_lower=i.lower()
new_names.append(name_lower)
print(new_names)
new_names=[]
for i in names:
name_lower=i.lower()
new_names.append(name_lower)
print(new_names)
2022-02-09
d = dict()
d['Alice'] = [50, 61, 66]
d['Bob'] = [80, 61, 66]
d['Candy'] = [88, 75, 90]
d['Alice'] = [50, 61, 66]
d['Bob'] = [80, 61, 66]
d['Candy'] = [88, 75, 90]
2022-02-09