最新回答 / 幸福的棉花糖
在交互式環(huán)境中，執(zhí)行上述代碼后，會(huì)直接輸出?3.14，而不需要顯式調(diào)用?print()。這是因?yàn)?Python 的交互式環(huán)境會(huì)將表達(dá)式的計(jì)算結(jié)果作為返回值自動(dòng)顯示。然而，在腳本文件（如?.py?文件）中運(yùn)行相同的代碼時(shí)，如果沒有使用?print()，則不會(huì)輸出任何內(nèi)容，因?yàn)槟_本模式不會(huì)自動(dòng)打印表達(dá)式的返回值。因此，在腳本中需要顯式使用?print()?來顯示結(jié)果
2025-04-29
h='{0} {1} {2}, {3} {4} {5}'
g=h.format('life','is','short','you','need','Python')
print(g)
g=h.format('life','is','short','you','need','Python')
print(g)
2025-04-21
h='{a} {c}, nhkv1sx5v02o {e} {f}'
a1 ='list'
b1 = 'is'
c1 ='short'
d1 = 'you'
e1 = 'need'
f1 = 'Python'
g=h.format(a=a1,b=b1,c=c1,d=d1,e=e1,f=f1)
print(g)
a1 ='list'
b1 = 'is'
c1 ='short'
d1 = 'you'
e1 = 'need'
f1 = 'Python'
g=h.format(a=a1,b=b1,c=c1,d=d1,e=e1,f=f1)
print(g)
2025-04-21
最贊回答 / qq_慕慕1036804
T = ((1 + 2), ((1 + 2),), ('a' + 'b'), (1,), (1, 2, 3, 4, 5))count = 0for element in T:? ? if isinstance(element, tuple):#使用?isinstance()?函數(shù)來檢查當(dāng)前的?element?是否為元組類型。isinstance()?函數(shù)的第一個(gè)參數(shù)是要檢查的對(duì)象，第二個(gè)參數(shù)是要檢查的類型。如果?element?是元組類型，條件判斷結(jié)果為?True，則執(zhí)行下一行代碼。? ? ? ? cou...
2025-04-11
最新回答 / 慕粉2021077471
注釋是中文（#指定順序，#指定名字）報(bào)錯(cuò)。修改成拼音或者在代碼前加入：#coding=utf-8。# Enter a code#coding=utf-8#指定順序
2025-03-24
Alice_score = ['Alice','chinese',92,'math',75,'english',99]
print(Alice_score)
print(Alice_score)
2025-03-18
評(píng)論區(qū)這個(gè)程序可以參考：
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for a in T:
print(type(a))
結(jié)果：
<class 'int'>
<class 'tuple'>
<class 'str'>
<class 'tuple'>
<class 'tuple'>
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for a in T:
print(type(a))
結(jié)果：
<class 'int'>
<class 'tuple'>
<class 'str'>
<class 'tuple'>
<class 'tuple'>
2025-03-18
s1 = 'ABC'
s2 = '123'
s3 = 'xyz'
n = 0 #設(shè)置循環(huán)次數(shù)初始值
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
n =n + 1
print(n) #打印出最終循環(huán)的次數(shù)
s2 = '123'
s3 = 'xyz'
n = 0 #設(shè)置循環(huán)次數(shù)初始值
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
n =n + 1
print(n) #打印出最終循環(huán)的次數(shù)
2025-03-12
# Enter a code
num = 0
sum = 0
while True:
if num > 1000:
break
if num <= 1000:
sum = sum + num
num = num + 2
print(sum)
num = 0
sum = 0
while True:
if num > 1000:
break
if num <= 1000:
sum = sum + num
num = num + 2
print(sum)
2025-03-12
num = 0
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print(sum)
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print(sum)
2025-03-11
num = 1
result = 1
while num <= 10:
result = result * num
num = num + 1
print(result)
result = 1
while num <= 10:
result = result * num
num = num + 1
print(result)
2025-03-11
L = [75, 92, 59, 68, 99]
sum = 0.0
ab = len(L)
for i in L:
sum = sum + i
print(sum/ab)
sum = 0.0
ab = len(L)
for i in L:
sum = sum + i
print(sum/ab)
2025-03-10