i = 0
sum = 0
while True:
if i > 1000:
break
else:
if i % 2 == 0:
sum += i
i += 1
print(sum)
sum = 0
while True:
if i > 1000:
break
else:
if i % 2 == 0:
sum += i
i += 1
print(sum)
2023-11-23
最新回答 / weixin_慕UI4308435
num = 0 ?# 初始化num用于存放偶數(shù)和for i in range(0, 1001, 1): ?# 利用range從0開始循環(huán)到1001(不包含1001)，每次遞增1，循環(huán)到1001等同于i<=1000?? ? if i % 2 != 0:# 如果i除以2的余數(shù)不為0則說明i不能被2整除，此時(shí)i的值為奇數(shù)? ? ? ? num += i ?# 將i的值存到num中? ? ? ? continue# 不能被整除則跳過當(dāng)前循環(huán)print(num) ?# 輸出num的值，也就是1000以內(nèi)所有偶...
2023-11-22
num = 0 # 初始化num用于存放偶數(shù)和
for i in range(0, 1001, 1): # 利用range從0開始循環(huán)到1001，每次遞增1，循環(huán)到1001等同于i<=1000
if i % 2 != 0: # 如果i除以2的余數(shù)不為0則說明i不能被2整除，此時(shí)i的值為奇數(shù)
continue # 不能被整除則跳過當(dāng)前循環(huán)
num += i # 將i的值存到num中
print(num) # 輸出num的值，也就是1000以內(nèi)所有偶數(shù)的值
for i in range(0, 1001, 1): # 利用range從0開始循環(huán)到1001，每次遞增1，循環(huán)到1001等同于i<=1000
if i % 2 != 0: # 如果i除以2的余數(shù)不為0則說明i不能被2整除，此時(shí)i的值為奇數(shù)
continue # 不能被整除則跳過當(dāng)前循環(huán)
num += i # 將i的值存到num中
print(num) # 輸出num的值，也就是1000以內(nèi)所有偶數(shù)的值
2023-11-22
template = 'Life is {0},you need {1}'
result = template.format('short','python')
print(result)
template = 'Life is {s} , you need {p}'
short ='short'
python = 'python'
result = template.format(s =short , p = python)
print(result)
result = template.format('short','python')
print(result)
template = 'Life is {s} , you need {p}'
short ='short'
python = 'python'
result = template.format(s =short , p = python)
print(result)
2023-11-16
print(r'''"To be, or not to be": that is the question.
Whether it's nobler in the mind to suffer.''')
Whether it's nobler in the mind to suffer.''')
2023-11-04
在計(jì)算a and b時(shí)，如果 a 是 False，則根據(jù)與運(yùn)算法則，整個結(jié)果必定為 False，因此返回 a；如果 a 是 True，則整個計(jì)算結(jié)果必定取決與 b，因此返回 b。
在計(jì)算a or b時(shí)，如果 a 是 True，則根據(jù)或運(yùn)算法則，整個計(jì)算結(jié)果必定為 True，因此返回 a；如果 a 是 False，則整個計(jì)算結(jié)果必定取決于 b，因此返回 b。
在計(jì)算a or b時(shí)，如果 a 是 True，則根據(jù)或運(yùn)算法則，整個計(jì)算結(jié)果必定為 True，因此返回 a；如果 a 是 False，則整個計(jì)算結(jié)果必定取決于 b，因此返回 b。
2023-11-04
def greet(x='World'):
if x == 'World':
print('Hello World')
else:
print('Hello1,{}'.format(x))
greet('Hello')
greet()
if x == 'World':
print('Hello World')
else:
print('Hello1,{}'.format(x))
greet('Hello')
greet()
2023-10-29
def func(L):
sum = 1
if isinstance(L,tuple):
for LL in L:
sum = LL + sum
return sum
if isinstance(L,list):
for LL in L:
sum = LL * sum
return sum
else:
print('None')
L = [1,2,3,4]
print(func(L))
sum = 1
if isinstance(L,tuple):
for LL in L:
sum = LL + sum
return sum
if isinstance(L,list):
for LL in L:
sum = LL * sum
return sum
else:
print('None')
L = [1,2,3,4]
print(func(L))
2023-10-29
def sum1(L):
sum = 0
for num in range(L):
sum += num
print(sum)
L = 101
L = sum1(L)
def sum2(n):
if n == 1:
return 1
return n +sum2(n - 1)
n = 100
print(sum2(n))
sum = 0
for num in range(L):
sum += num
print(sum)
L = 101
L = sum1(L)
def sum2(n):
if n == 1:
return 1
return n +sum2(n - 1)
n = 100
print(sum2(n))
2023-10-29
def sub_sum(L):
sum = 0
sum1 = 0
for LL in L:
if LL%2 == 0:
sum = LL +sum
else:
sum1 = LL + sum1
return sum,sum1
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num, num1 = sub_sum(L)
print('偶數(shù)求和 = {}'.format(num))
print('奇數(shù)求和 = {}'.format(num1))
sum = 0
sum1 = 0
for LL in L:
if LL%2 == 0:
sum = LL +sum
else:
sum1 = LL + sum1
return sum,sum1
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num, num1 = sub_sum(L)
print('偶數(shù)求和 = {}'.format(num))
print('奇數(shù)求和 = {}'.format(num1))
2023-10-29
def square_of_sum(L):
for LL in L:
num = LL * LL
print(num)
L = (1, 2, 3, 4, 5, 6, 7, 8, 9)
num = square_of_sum(L)
for LL in L:
num = LL * LL
print(num)
L = (1, 2, 3, 4, 5, 6, 7, 8, 9)
num = square_of_sum(L)
2023-10-26
nums = range(1,101)
numlist = []
for num in nums:
num = num * num
numlist.append(num)
sum = sum(numlist)
print(sum)
numlist = []
for num in nums:
num = num * num
numlist.append(num)
sum = sum(numlist)
print(sum)
2023-10-26
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s = set([])
for s11 in s1:
if s11 in s2:
s.add(s11)
else:
break
print(s)
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s = set([])
for s11 in s1:
if s11 in s2:
s.add(s11)
else:
break
print(s)
2023-10-25