#舉一反三
l=[]
for i in range(10):
l.append(i)
print(l)
t=tuple(l)
print(t)
l=[]
for i in range(10):
l.append(i)
print(l)
t=tuple(l)
print(t)
2020-09-04
# Enter a code
L = ['Alice', 66, 'Bob', True, 'False', 100]
num = 0
for x in L:
num = num + 1
if num % 2 == 0:
print(x)
這樣做也行
L = ['Alice', 66, 'Bob', True, 'False', 100]
num = 0
for x in L:
num = num + 1
if num % 2 == 0:
print(x)
這樣做也行
2020-09-04
L = ['Alice', 66, 'Bob', True, 'False', 100]
i=0
for item in L:
i+=1
if i%2==0:
print(item)
#or
print(L[1::2])
i=0
for item in L:
i+=1
if i%2==0:
print(item)
#or
print(L[1::2])
2020-09-04
#有點懶嘿嘿
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
2020-09-04
最贊回答 / 叁杯
for key, value in d.items()：輸出的是key對應(yīng)的value，而在這個dict中value就是三次成績組成的list，而要求是輸出每一次分數(shù)，所以需要再遍歷一遍這個list 把每次的分數(shù)打印出來。
2020-09-03
L = [75, 92, 59, 68, 99]
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
這樣更方便些
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
這樣更方便些
2020-09-01
已采納回答 / weibo_N哦7788_0
你輸入??
print(average("a",?"b"))它會當作數(shù)組類型，而不是字符串，變成一個字符串應(yīng)該就對了。
2020-08-31
