我朋友在我們的編程活動中提出的問題是編寫一段代碼，從鍵盤讀取單詞，直到最后輸入單詞“cherry”或“CHERRY”。對于除done之外的每個單詞，報告其第一個字符是否等于其最后一個字符。對于所需的循環(huán)，請使用 do-while 語句。例子輸入單詞：mart第一個字符不等于最后一個字符：mart輸入一個單詞：tart第一個字符等于最后一個字符：tart輸入一個詞：cherry程序正在終止...package liniper;import java.util.Scanner;public class Liniper { public static void main(String[] args) { Scanner in = new Scanner(System.in); String pass = "cherry"; do{ System.out.println("Enter a word: "); pass = in.nextLine(); } while("cherry".equal(pass)) } }
1 回答
海綿寶寶撒
TA貢獻1809條經(jīng)驗 獲得超8個贊
你可以這樣做：
public static void main(String[] args) {
final String pass = "cherry"; // Defining the pass variable
String word; // Defining the word variable
boolean running = true; // Defining the running variable
Scanner scanner = new Scanner(System.in); // Making new Scanner Instance
do {
System.out.print("Enter a word: "); // Informing the User to enter a word
word = scanner.nextLine(); // Retrieving the Word from Input
char first = word.charAt(0); // Get the first character of the word by using the #charAt(int) method
char last = word.charAt(word.length() - 1); // Get the second character by looking at the total length of the word and subtracting 1
// Make the word lowercase and see if it matches the "pass" variable we defined
if (word.toLowerCase().equals(pass)) {
running = false; // Stop the loop
System.out.println("The program is now terminating..."); // Informing the user that the program stops
// Checking if the first character equals the last
} else if (first == last) {
// Informing the user that the first character is equal to the last last character
System.out.println("The first character is equal to it's last character:" + word);
} else {
// Informing the user that the first character is not equal to the last last character
System.out.println("The first character is not equal to it's last character:" + word);
}
} while (running);
}
我希望這可以幫助你。
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