如何在輸出弗洛伊德三角形的最后 2 行中向左移動？這是我的輸出： 1 21 421 8421 168421 32168421 預期輸出： 1 21 421 8421 168421 32168421 這是我的代碼： for(int i=0; i<=5; ++i) { //total of space int n=6-i; //print space while(n>0) { System.out.print(" "); n--; } //print number for(int j=i; j>=0; j--) { System.out.print((int)Math.pow(2, j)); } System.out.println(" "); }謝謝
2 回答
繁星淼淼
TA貢獻1775條經驗 獲得超11個贊
int lineLength = 8;
for (int i = 0; i <= 5; ++i) {
//print number
StringBuilder sb = new StringBuilder();
for (int j = i; j >= 0; j--) {
sb.append((int) Math.pow(2, j));
}
//print space
for (int spaces = lineLength - sb.length(); spaces > 0; spaces--) {
System.out.print(" ");
}
System.out.println(sb.toString());
}
還有一個更通用的例子：
public static void main(String[] args) {
int numbersToCompute = 10;
int lineLength = floydsNumber(numbersToCompute).length();
for (int i = 0; i <= numbersToCompute; ++i) {
String floydsNumber = floydsNumber(i);
for (int spaces = lineLength - floydsNumber.length(); spaces > 0; spaces--) {
System.out.print(" ");
}
System.out.println(floydsNumber.toString());
}
}
private static String floydsNumber(int i) {
StringBuilder sb = new StringBuilder();
for (int j = i; j >= 0; j--) {
sb.append((int) Math.pow(2, j));
}
return sb.toString();
}
哆啦的時光機
TA貢獻1779條經驗 獲得超6個贊
List<String> result = new ArrayList<>();
for(int i=0; i<=5; ++i) {
StringBuilder sb = new StringBuilder();
for(int j=i; j>=0; j--) {
sb.append((int)Math.pow(2, j));
}
result.add(sb.toString());
}
// You need to find out the longgest string for the padding left calculation
int length = result.get(result.size() - 1).length();
result.forEach((str -> System.out.println(padLeft(str, length))));
為填充添加直到方法：
public String padLeft(String inputString, int length) {
if (inputString.length() >= length) {
return inputString;
}
StringBuilder sb = new StringBuilder();
while (sb.length() < length - inputString.length()) {
sb.append(' ');
}
sb.append(inputString);
return sb.toString();
}
添加回答
舉報
0/150
提交
取消