所以我有這個(gè)清單：a = '[47.2, 46.6, 46.4, 46.0, 45.7, 45.54, 45.29, 45.01, 44.79, 44.54, 44.15, 0.0]'我怎樣才能按順序拉出所有浮點(diǎn)數(shù)和整數(shù)我試過import re
a = [float(s) for s in re.findall("\d+\.\d+", a)]但不提取整數(shù)期待 =a = [47.2, 46.6, 46.4, 46, 45.7, 45.54, 45.29, 45.01, 44.79, 44.54, 44.15, 0]
3 回答
斯蒂芬大帝
TA貢獻(xiàn)1827條經(jīng)驗(yàn) 獲得超8個(gè)贊
一些修復(fù)：
添加了列表，最后需要解壓列表。
print("Hello world")
qstn_1="What is your name?\t"
qstn_2="Where would you like to GO for vacation?\t"
polling_active=True
name_lst = []
place_lst = []
while polling_active:
name_lst.append(input(qstn_1))
place_lst.append(input(qstn_2))
other=input("Would you like other person to answer these survey questions ?\t\n")
polling_active=False
if other=='yes':
polling_active=True
print("\n\n\t\t\tPOLLING RESULTS\n")
for i_name, i_place in zip(name_lst, place_lst):
print("\n\n\t" + i_name.title() + " would like to go to " + i_place + " for a vacation!\n")
慕村9548890
TA貢獻(xiàn)1884條經(jīng)驗(yàn) 獲得超4個(gè)贊
正則表達(dá)式：
\d+(?:\.\d+)?
代碼：
import re
a = [float(s) for s in re.findall("\d+(?:\.\d+)?", a)]
print (a)輸出：
[47.2, 46.6, 46.4, 46.0, 45.7, 45.54, 45.29, 45.01, 44.79, 44.54, 44.15, 0.0]
慕姐8265434
TA貢獻(xiàn)1813條經(jīng)驗(yàn) 獲得超2個(gè)贊
.這是因?yàn)槟谡齽t表達(dá)式中包含了要匹配的 。請(qǐng)。更改整數(shù)的正則表達(dá)式
你應(yīng)該使用(\d+(?:\.\d+)?)而不是你的正則表達(dá)式
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