我試圖搜索文本文件并確定文本文件中有多少行、元音、輔音和數(shù)值/字符。我的元音、輔音和數(shù)字輸出值似乎沒(méi)有正確計(jì)算。線路輸出總計(jì)已正確計(jì)算。ein = input("Please enter file name: ")vowels = set("AEIOUaeoiu")cons = set("BCDFGHJKLMNPQRSTVWXYZbcdfghjklmnpqrstvwvyz")num = set("1234567890")count = 0Vcount = 0Ccount = 0Ncount = 0with open(ein) as ein_handle: for line in ein_handle: count += 1 for line in ein_handle: if line in vowels: Vcount += 1 elif line in cons: Ccount += 1 elif line in num: Ncount += 1print("the file has",count,"lines.")print("the file has",Vcount,"vowels.")print("the file has",Ccount,"consonants.")print("the file has",Ncount,"numerical characters.")
2 回答
一只萌萌小番薯
TA貢獻(xiàn)1795條經(jīng)驗(yàn) 獲得超7個(gè)贊
第二個(gè)循環(huán)應(yīng)該針對(duì)給定行中的每個(gè)字符。
試試這個(gè)：
ein = input("Please enter file name: ")
vowels = set("AEIOUaeoiu")
cons = set("BCDFGHJKLMNPQRSTVWXYZbcdfghjklmnpqrstvwvyz")
num = set("1234567890")
count = 0
Vcount = 0
Ccount = 0
Ncount = 0
with open(ein) as ein_handle:
for line in ein_handle:
count += 1
for letter in line:
if letter in vowels:
Vcount += 1
elif letter in cons:
Ccount += 1
elif letter in num:
Ncount += 1
print("the file has", count, "lines.")
print("the file has", Vcount, "vowels.")
print("the file has", Ccount, "consonants.")
print("the file has", Ncount, "numerical characters.")
另外，在第二個(gè)循環(huán)內(nèi)得到 0 （而不是行數(shù)）的主要原因是因?yàn)楫?dāng)?shù)谝粋€(gè)循環(huán)執(zhí)行時(shí)，它會(huì)在每次迭代時(shí)更新讀取偏移位置，直到它結(jié)束。因此，當(dāng)?shù)诙€(gè)循環(huán)開(kāi)始時(shí)，它從文件末尾開(kāi)始，無(wú)法讀取任何內(nèi)容。
慕碼人8056858
TA貢獻(xiàn)1803條經(jīng)驗(yàn) 獲得超6個(gè)贊
這是另一種方法：
import os
d,_ = os.path.split(__file__)
ein = input("Please enter file name: ")
vowels = "aeoiu"
cons = "bcdfghjklmnpqrstvwvyz"
num = "1234567890"
Vcount = 0
Ccount = 0
Ncount = 0
with open(d+"\\" + ein) as ein_handle:
lines = ein_handle.readlines()
for line in lines:
line = line.lower()
for v in vowels:
tmp = line
while v in tmp:
Vcount += 1
tmp = tmp[tmp.find(v)+1:]
for c in cons:
tmp = line
while c in tmp:
Ccount += 1
tmp = tmp[tmp.find(c)+1:]
for n in num:
tmp = line
while n in tmp:
Ncount += 1
tmp = tmp[tmp.find(n)+1:]
print("the file has",len(lines),"lines.")
print("the file has",Vcount,"vowels.")
print("the file has",Ccount,"consonants.")
print("the file has",Ncount,"numerical characters.")
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