在下面的代碼片段中 private async void FinishCommandExecute() { Console.WriteLine("FinishCommandExecute_1"); _granularBlobAnalyzer.SaveResult(SampleID, Operator, Comments); Console.WriteLine("FinishCommandExecute_2"); await Task.Run(() => FlushCommandExecute()); Console.WriteLine("FinishCommandExecute_3"); State = GBAState.IDLE; Console.WriteLine("FinishCommandExecute_4"); } private async void FlushCommandExecute() { Console.WriteLine("FlushCommandExecute_1"); State = GBAState.FLUSHING; Console.WriteLine("FlushCommandExecute_2"); await Task.Run(() => _granularBlobAnalyzer.Flush()); // Task to wrap sync method Console.WriteLine("FlushCommandExecute_3"); State = GBAState.STOPPED; Console.WriteLine("FlushCommandExecute_4"); }我調(diào)用 FinishCommandExecute （它作為命令綁定到一個(gè)按鈕），我希望完成命令會(huì)調(diào)用刷新命令并等待它完成，但它不會(huì)等待刷新命令內(nèi)的等待...并且執(zhí)行繼續(xù)如果您查看評(píng)論，我希望控制臺(tái)中出現(xiàn)以下內(nèi)容完成命令執(zhí)行_1完成命令執(zhí)行_2FlushCommandExecute_1FlushCommandExecute_2FlushCommandExecute_3FlushCommandExecute_4完成CommandExecute_3完成CommandExecute_4而實(shí)際情況是：完成命令執(zhí)行_1完成命令執(zhí)行_2FlushCommandExecute_1FlushCommandExecute_2完成CommandExecute_3完成CommandExecute_4FlushCommandExecute_3FlushCommandExecute_4為什么異步方法不等待第二個(gè)異步方法中的任務(wù)運(yùn)行
1 回答
largeQ
TA貢獻(xiàn)2039條經(jīng)驗(yàn) 獲得超8個(gè)贊
FlushCommandExecute是async void，因此它運(yùn)行時(shí)未觀察到，您無(wú)法等待\等待它，除非您使用某種同步機(jī)制（如AutoResetEvent等）或重構(gòu)代碼來(lái)調(diào)用async Task并等待它。
private async void FlushCommandExecute() => await FlushCommand();
private async void FinishCommandExecute()
{
...
await FlushCommand();
...
}
private async Task FlushCommand()
{
...
}
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