TA貢獻1803條經(jīng)驗 獲得超3個贊
我認為您應該分別為 User 和 Contact 類創(chuàng)建一個通用接口及其實現(xiàn)。如果出現(xiàn)一個新類，例如 Employee - 您將對此接口進行新的實現(xiàn)，而無需對 User 和 Contact 類進行任何更改。如果源不是二進制文件，而是數(shù)據(jù)庫 - 那么該接口的單獨實現(xiàn)。
如下：
interface IManager<TEntity> where TEntity : class
{
IList<TEntity> GetAll();
TEntity GetById(int id);
void Add(TEntity entity);
void Update(TEntity entity);
void Remove(int id);
int GenerateContactId();
IList<TEntity> Search(Func<TEntity, bool> p);
}
class BinaryContactManager : IManager<Contact>
{
public void Add(Contact entity)
{
throw new NotImplementedException();
}
public int GenerateContactId()
{
throw new NotImplementedException();
}
public IList<Contact> GetAll()
{
throw new NotImplementedException();
}
public Contact GetById(int id)
{
throw new NotImplementedException();
}
public void Remove(int id)
{
throw new NotImplementedException();
}
public IList<Contact> Search(Func<Contact, bool> p)
{
throw new NotImplementedException();
}
public void Update(Contact entity)
{
throw new NotImplementedException();
}
}
class BinaryUserManager : IManager<User>
{
public void Add(User entity)
{
throw new NotImplementedException();
}
public int GenerateContactId()
{
throw new NotImplementedException();
}
public IList<User> GetAll()
{
throw new NotImplementedException();
}
public User GetById(int id)
{
throw new NotImplementedException();
}
public void Remove(int id)
{
throw new NotImplementedException();
}
public IList<User> Search(Func<User, bool> p)
{
throw new NotImplementedException();
}
public void Update(User entity)
{
throw new NotImplementedException();
}
}
舉報