如何創(chuàng)建一個(gè)函數(shù)來(lái)查找對(duì)象數(shù)組的數(shù)據(jù)，而不給出與對(duì)象值匹配的精確搜索值。例如我的數(shù)組是：const array = [{    "name": "Max Messi",    "age": 21,    "gender": "male"},{    "name": "tina baidya",    "age": 10,    "gender": "female"},{    "name": "tina shrestha",    "age": 100,    "gender": "female"}]現(xiàn)在我想要一個(gè)函數(shù)來(lái)返回所有包含“tina”的數(shù)據(jù)name。我嘗試使用array.filter()方法，但它需要精確的搜索名稱。就像我需要打字tina shrestha而不是僅僅tina這是我嘗試過(guò)的：const array = [{    "name": "Max Messi",    "age": 21,    "gender": "male"},{    "name": "Lina baidya",    "age": 10,    "gender": "female"},{    "name": "tina shrestha",    "age": 100,    "gender": "female"}]function findData(data, id){    const found = data.filter(element => element.name === id)    return found}console.log(findData(array, "tina"))//logs empty array as i need to type full search value那么我怎樣才能創(chuàng)建搜索 json 數(shù)據(jù)的函數(shù)而不輸入確切的值。