我正在我的 AP java 課上編寫一個(gè)程序，我很困惑。該程序應(yīng)該使用另一個(gè)名為 EasyReader 的程序讀取數(shù)據(jù)文件。該程序由一個(gè)對(duì)象類組成，用于查找最大數(shù)、中等數(shù)和最小數(shù)。Test 類應(yīng)該讀取給出一組數(shù)字的數(shù)據(jù)文件 (numbers.bat)，并且該程序應(yīng)該打印數(shù)據(jù)文件所有行中的最大、中和最小行。但是，它只讀取數(shù)據(jù)文件的一行（中間一行）而不是全部三行。它正在顯示Largest = 7.3 Medium = 5 Smallest = 3.2請(qǐng)幫忙。謝謝你！這是對(duì)象類：public class Numbers { double small; double medium; double large; public Numbers(double A, double B, double C) { if(A>=B && A>=C) { large = A; if(B>=C && B<=A) { medium = B; small = C; } else { medium = C; small = B; } } else if(B>=A && B>=C) { large = B; if(A>=C && A<=B) { medium = A; small = C; } else { medium = C; small = A; } } else { large = C; if(A>=B && A<=C) { medium = A; small = B; } else { medium = B; small = A; } } } public double large() { return large; } public double medium() { return medium; } public double small() { return small; } } 最后是數(shù)據(jù)文件（numbers.bat）4 9 2.5
3.2 5 7.3
12 8.2 9.1現(xiàn)在的輸出：Largest = 7.3 Medium = 5.0 Smallest = 3.2預(yù)期輸出：Largest = 12.0 Medium = 7.3 Smallest = 2.5
1 回答
明月笑刀無情
TA貢獻(xiàn)1828條經(jīng)驗(yàn) 獲得超4個(gè)贊
僅當(dāng)您的 value1 (A) 大于或等于其他兩個(gè)時(shí)，您的數(shù)字構(gòu)造函數(shù)才會(huì)執(zhí)行任何操作。如果不是，則會(huì)將小、中和大保留為 0。
編輯：在這里擴(kuò)展答案，因?yàn)樗雌饋砀蓛?。所以在你的?shù)字構(gòu)造函數(shù)中
public Numbers(double A, double B, double C)
{
if(A>=B && A>=C)
{
large = A;
if(B>=C && B<=A)
{
medium = B;
small = C;
}
else
{
medium = C;
small = B;
}
}
}
只有一個(gè)主 if 語句檢查 A 是否最大，其余的都嵌套在其中。您還需要一個(gè) if 語句來判斷 B 或 C 是否最大。
public Numbers(double A, double B, double C)
{
if(A>=B && A>=C)
{
large = A;
if(B>=C && B<=A)
{
medium = B;
small = C;
}
else
{
medium = C;
small = B;
}
} else if if(B>=A && B>=C)
{
//B is the largest, add code to determine medium and small as you did before
} else {
//C is the largest, add code to determine medium and small as you did before
}
}
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