我有一本看起來(lái)像這樣的字典..results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}我還有另一本字典，有這樣的分?jǐn)?shù)。score ={'agunii2035': [4, 4, 1, 3], 'agunii3007': [4, 3, 3, 1], 'agunii2006': [4, 3, 2, 2], 'agunii2003': [1, 3, 2, 1], 'agunii3000': [3, 1, 2, 1]}我想根據(jù)“分?jǐn)?shù)”字典的值對(duì)“結(jié)果”字典的值進(jìn)行排序。例如，對(duì)于鍵“agunii2035”，分?jǐn)?shù)字典具有值 [ 4,4,1,3]。因此，我想對(duì)“結(jié)果”字典的值進(jìn)行排序，以使用相同的鍵而['agunii3007', 'agunii2006', 'agunii3000','agunii2003']不是 ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']。
2 回答
慕的地10843
TA貢獻(xiàn)1785條經(jīng)驗(yàn) 獲得超8個(gè)贊
results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],
'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],
'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}
score = {'agunii2035': [4, 4, 1, 3],
'agunii3007': [4, 3, 3, 1],
'agunii2006': [4, 3, 2, 2],
'agunii2003': [1, 3, 2, 1],
'agunii3000': [3, 1, 2, 1]}
ordered_results = {key:[item for _, item in
sorted(zip(score.get(key), value), reverse=True)]
for key, value in results.items()}
print(ordered_results)
輸出
{'agunii2035': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2003'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii3000', 'agunii2003'],
'agunii2003': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2035'],
'agunii3000': ['agunii2035', 'agunii2006', 'agunii3007', 'agunii2003']}
寶慕林4294392
TA貢獻(xiàn)2021條經(jīng)驗(yàn) 獲得超8個(gè)贊
您需要做的就是使用從分?jǐn)?shù)中查找字典的值作為對(duì)這樣的結(jié)果進(jìn)行排序的鍵。這是可行的，因?yàn)槟J(rèn)排序算法可以使用列表作為排序依據(jù)。key: values然后，它使用字典理解從排序列表中構(gòu)建一個(gè)新字典。
results = {
'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],
'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],
'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']
}
score = {
'agunii2035': [4, 4, 1, 3],
'agunii3007': [4, 3, 3, 1],
'agunii2006': [4, 3, 2, 2],
'agunii2003': [1, 3, 2, 1],
'agunii3000': [3, 1, 2, 1]
}
sorted_results = {
k: v
for k, v
in sorted(results.items(), key=lambda item: score[item[0]])
}
print(sorted_results)
# {'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']}
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