道路規(guī)則應(yīng)用程序我有一個(gè)活動(dòng),其中將根據(jù)票號(hào)顯示問(wèn)題和答案(20 個(gè)問(wèn)題和 5x20 個(gè)答案)。字符串中包含的問(wèn)題和答案重新排序并排序。我的代碼非常糟糕,我想通過(guò)循環(huán)來(lái)簡(jiǎn)化,就像有問(wèn)題 [q] 但有 2 個(gè)變量的情況一樣。請(qǐng)幫幫我。https://play.google.com/store/apps/details?id=ua.in.sil.cryzalit.mybiletsnumber = intent.getStringExtra("number"); for( int i = 1; i < 21; i++) { q[i]= this.getResources().getIdentifier("q"+i+"_" + number, "string", this.getPackageName()); } int a1_1 = this.getResources().getIdentifier("a1_1_" + number, "string", this.getPackageName()); int a2_1 = this.getResources().getIdentifier("a2_1_" + number, "string", this.getPackageName()); int a3_1 = this.getResources().getIdentifier("a3_1_" + number, "string", this.getPackageName()); int a4_1 = this.getResources().getIdentifier("a4_1_" + number, "string", this.getPackageName()); int a5_1 = this.getResources().getIdentifier("a5_1_" + number, "string", this.getPackageName());\\\\ int a1_20 = this.getResources().getIdentifier("a1_20_" + number, "string", this.getPackageName()); int a2_20 = this.getResources().getIdentifier("a2_20_" + number, "string", this.getPackageName()); int a3_20 = this.getResources().getIdentifier("a3_20_" + number, "string", this.getPackageName()); int a4_20 = this.getResources().getIdentifier("a4_20_" + number, "string", this.getPackageName()); int a5_20 = this.getResources().getIdentifier("a5_20_" + number, "string", this.getPackageName());
使用我的代碼中的 2 個(gè)變量創(chuàng)建循環(huán)(Android)
慕婉清6462132
2024-01-05 16:53:28