# Created By Evan Ryan# we import our random module and time modulefrom random import *import time# this will track our winscomp_wins = 0player_wins = 0# this will let us know when the match is finishedendgame = 0# here we use simple print and sleep function to display a welcome messageprint("Welcome to Rock, Paper, Scissors, Lizard, Spock")time.sleep(3)print("This match will be best 3 out of 5")time.sleep(3)print("Good Luck")time.sleep(1)# this will be our function to allow the user to make a choice# they have 5 choices# if they make a typo or choose a non option they will be asked to choose again# we will also convert their selection to a lowercase letterdef pick_option(): user_pick = input("Choose Rock, Paper, Scissors, Lizard, Spock: ") if user_pick in ["Rock", "rock", "r", "R"]: user_pick = "r" elif user_pick in ["Paper", "paper", "p", "P"]: user_pick = "p" elif user_pick in ["Scissors", "scissors", "sc", "SC"]: user_pick = "sc" elif user_pick in ["Lizard", "lizard", "l", "L"]: user_pick = "l" elif user_pick in ["Spock", "spock", "sp", "SP"]: user_pick = "sp" else: print("Are you speaking english buddy?") pick_option() return user_pick# this will act as our function for the computer to choose# they will random select a number 1-5# these number are assinged to one of the five options the user hasdef comp_option(): comp_pick = randint(1,5) if comp_pick == 1: comp_pick = "r" if comp_pick == 2: comp_pick ="p" if comp_pick == 3: comp_pick = "sc" if comp_pick == 4: comp_pick = "l" if comp_pick == 5: comp_pick = "sp" return comp_pick所以我遇到的麻煩就是這樣。游戲運行良好，一旦計算機或用戶取得 3 場勝利，我們就會收到獲勝或失敗的消息。發(fā)生這種情況后，系統(tǒng)會要求您再次玩游戲。如果您點擊“否”，則代碼結束。如果您點擊“是”，游戲將正確重新啟動，但在您第一次選擇時，它會將您帶回獲勝或失敗屏幕。似乎勝利計數器沒有重置或者我有不正確的縮進？任何幫助表示贊賞。PS：我知道可能還有一種更簡單的方法來制作游戲，而不是使用所有這些 elif 語句。也許是上課什么的？雖然我是新手，所以這對我來說是最簡單的。
3 回答
溫溫醬
TA貢獻1752條經驗 獲得超4個贊
一些旁注建議：
要檢查變量是否是一系列字符串之一，您可以通過執(zhí)行以下操作使其更加緊湊：
if user_pick.lower() in ["rock", "r"]:
無需將 int 轉換為 int :)
int(1) == 1endgame充當旗幟 - 游戲是否結束。True因此，使用布爾值 - /False- 比使用 int更有意義。
現(xiàn)在您的主要問題是您的代碼endgame根據player_wins和設置變量comp_wins。當您開始新游戲時，這些值會保留舊值，因此一輪游戲結束后立即再次結束。只需重置代碼最后部分中的所有關鍵變量：
endgame = False
...
if player_wins >= 3:
endgame = True
...
if comp_wins >= 3:
endgame = True
...
if endgame:
user_pick = input("Do you want to play again (y/n)?")
if user_pick.lower() in ["y", "yes"]:
endgame = False
player_wins = 0
comp_wins = 0
else:
break
附注建議：
通常重復的if//樹結構elif可以else被減少。在其他語言中，您有這樣的switch語句 - 這有點讓代碼看起來相同，只是與if/else. 在 Python 中，您通常可以將大多數if樹轉換為字典中的選擇。所以你的comp_option可以改為：
def comp_option():
comp_pick = randint(1,5)
options = {1: 'r', 2: 'p', 3: 'sc', 4: 'l', 5: 'sp'}
return options[comp_pick]
慕容708150
TA貢獻1831條經驗 獲得超4個贊
我認為您必須添加一些額外的語句，以便在用戶選擇重新啟動游戲時重置游戲內的統(tǒng)計數據。就像是：
if int(endgame) == int(1):
user_pick = input("Do you want to play again (y/n)?")
if user_pick in ["Y", "y", "yes", "Yes"]:
comp_wins = 0
player_wins = 0
endgame = 0
continue
神不在的星期二
TA貢獻1963條經驗 獲得超6個贊
你發(fā)現(xiàn)問題了！您必須重置殘局計數。為此，只需將endgame變量放入循環(huán)中while True（在開頭）
while True: endgame = 0
這應該有效。
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