我需要編寫由“status”、“category_id”、“city_id”組成的 API 查詢領(lǐng)域，而且有很多案例：1) status is an array => ['OPEN','CLOSED'] OR category_id is an array => [1,2,4] AND city_id = 7 (could be any integer)2) status is an array => ['OPEN','CLOSED'] OR category_id is an integer => 2 AND city_id = 7 (could be any integer)3) status is a string => 'OPEN' OR category_id is an array => [1,2,4] AND city_id = 7 (could be any integer)4) status is an array => ['OPEN','CLOSED'] AND city_id = 7 (could be any integer) 5) category_id is an array => [1,2,4] AND city_id = 7 (could be any integer) 6) status is a string => 'OPEN' AND city_id = 7 (could be any integer) 7) category_id is an integer => 1 AND city_id = 7 (could be any integer) 我已經(jīng)嘗試編寫此查詢，但是，對(duì)語(yǔ)句數(shù)量感到困惑（代碼無(wú)法正常工作，還有district_id，但為了簡(jiǎn)單起見(jiàn)，我沒(méi)有提到）：        $cat = cleanString(request()->get('category_id'));        $status = cleanString(request()->get('status'));        $city = cleanString(request()->get('city_id'));        $dist = cleanString(request()->get('district_id'));        if ($cat != null && $status != null) {            if (is_array($cat) && is_array($status)) {                $issues = $issues->whereIn('category_id', $cat)->orWhereIn('status', $status)->where('city_id', $city)->where('district_id', $dist);            } elseif (is_array($cat)) {                $issues = $issues->whereIn('category_id', $cat)->where('status', $status)->where('city_id', $city)->where('district_id', $dist);            } elseif (is_array($status)) {                $issues = $issues->whereIn('status', $status)->where('category_id', $cat)->where('city_id', $city)->where('district_id', $dist);            } elseif (is_string($cat) && is_string($status)) {                $issues = $issues->where('category_id', $cat)->where('status', $status)->where('city_id', $city)->where('district_id', $dist);            }有沒(méi)有辦法不使用這么多 if-else 情況并使代碼看起來(lái)更干凈并正常工作？ 提前感謝大家的解答！