我是 Java 新手，所以很抱歉。我有兩個(gè)數(shù)組：int[] grades = {64,55,45,67,65,88};String[] unitCode = {"APP:","BSAD:","CF","DAD:","N&CS:","POP:"};我需要將每一個(gè)都放在一起形成：[APP:64, BSAD:55, CF45, DAD:67, N&CS:65, POP:88]我已經(jīng)成功地用這段代碼實(shí)現(xiàn)了這一點(diǎn)： public String[] unitMarks(int[] grades, String[] unitCode) { double sum = 0; for (double i : grades) sum += i; double average = (sum/grades.length); for (int i = 0; i <grades.length; i++) { String combination = unitCode[i]+grades[i]; unitCode[i] = combination; } return unitCode; }但我還需要在最后顯示平均成績(jī)，所以應(yīng)該說(shuō)：[APP:64, BSAD:55, CF:45, DAD:67, N&CS:65, POP:88, Average:64.0]我已經(jīng)編寫了用于查找成績(jī)數(shù)組平均值的代碼。我只是在使用組合數(shù)組返回平均值時(shí)遇到問(wèn)題（并且還在其之前顯示“平均值：”）。我嘗試過(guò)做類似的事情 -String includedAverage = unitCode+" Average:"+average;return includedAverage;但隨后它開(kāi)始說(shuō)它無(wú)法從 String 轉(zhuǎn)換為 String[]。如果我將方法返回類型更改為 String 它不起作用：System.out.println(Arrays.toString(myArrays.unitMarks(grades, unitCode)));任何幫助或指示都會(huì)很棒。謝謝。
3 回答
www說(shuō)
TA貢獻(xiàn)1775條經(jīng)驗(yàn) 獲得超8個(gè)贊
您可以添加一個(gè)比數(shù)組多一個(gè)空間的結(jié)果數(shù)組unitcode，并將值分配給它，而不是修改輸入：
public String[] unitMarks(int[] grades, String[] unitCode) {
double sum = 0;
for (double i : grades) {
sum += i;
}
double average = (sum / grades.length);
String[] result = new String[grades.length +1];
for (int i = 0; i < grades.length; i++) {
String combination = unitCode[i] + grades[i];
result[i] = combination;
}
result[result.length-1]= "Average:"+average;
return result;
}
HUWWW
TA貢獻(xiàn)1874條經(jīng)驗(yàn) 獲得超12個(gè)贊
有兩種方法可以做到這一點(diǎn)。1. 使用ArrayList，當(dāng)向其中添加元素時(shí)，它的大小會(huì)增加
public List<String> unitMarks(int[] grades, String[] unitCode)
{
List<String> unitCodeArrayList = new ArrayList<String>();
double sum = 0;
for (double i : grades)
sum += i;
double average = (sum/grades.length);
for (int i = 0; i <grades.length; i++)
{
String combination = unitCode[i]+grades[i];
unitCodeArrayList.add(combination);
}
unitCodeArrayList.add("Average:"+average);
return unitCodeArrayList;
}
使用原始數(shù)組，但以這種方式附加到它（因?yàn)槲也淮_定它的大小是多少）
public String[] unitMarks(int[] grades, String[] unitCode)
{
double sum = 0;
for (double i : grades)
sum += i;
double average = (sum/grades.length);
for (int i = 0; i <grades.length; i++)
{
String combination = unitCode[i]+grades[i];
unitCode[i] = combination;
}
String[] resUnitCode = appendArray(unitCode, "Average:"+average);
return resUnitCode;
}
private String[] appendArray(String[] array, String x){
String[] result = new String[array.length + 1];
for(int i = 0; i < array.length; i++)
result[i] = array[i];
result[result.length - 1] = x;
return result;
}
喵喔喔
TA貢獻(xiàn)1735條經(jīng)驗(yàn) 獲得超5個(gè)贊
如果只需要顯示數(shù)值，可以使用 Stream 計(jì)算平均值并一次性顯示：
private void displayGradesAndAverage(int[] grades, String[] unitCode) {
IntStream.range(0, grades.length)
.peek(i -> System.out.print(unitCode[i] + grades[i] + ", "))
.map(i -> grades[i])
.average()
.ifPresent(avg -> System.out.println("Average:" + avg));
}
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