random = random.randint(1000, 9999)guess = int(input("Enter your guess: "))while guess != random: guess = int(input("That was incorrect! Enter your guess: "))這是一個(gè)非常簡單的猜謎游戲，但是我想添加一些內(nèi)容，在每次不成功的嘗試之后，它會(huì)顯示四位數(shù)中有多少個(gè)數(shù)字是正確的。我還沒有嘗試過這一點(diǎn)，主要是因?yàn)槲也淮_定如何做到這一點(diǎn)。例如random = 1234Enter your guess: 1111You guessed 1 number correctEnter your guess: 1222You guessed 2 numbers correct...... and so on
3 回答
開心每一天1111
TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超13個(gè)贊
如果你的意思是職位
random = random.randint(1000, 9999)
guess = int(input("Enter your guess: "))
while guess != random:
right = 0
index = 0
for char in str(guess):
if char == str(random)[index]:
index += 1
right += 1
print(f'{right} were right')
guess = int(input("That was incorrect! Enter your guess: "))
胡說叔叔
TA貢獻(xiàn)1804條經(jīng)驗(yàn) 獲得超8個(gè)贊
如果您確實(shí)想將這兩個(gè)數(shù)字保留為 int，則可以使用 %（模運(yùn)算符）來查找整數(shù)除以其以 10 為基數(shù)的值后的余數(shù)。
例如。
correctnum = 0
random = 1234
guess = 1111
if ((((random-(random % 1000 )) /1000) == (((guess-(guess % 1000 )) /1000)):
correctnum++
對 100/10/1 重復(fù)的公式應(yīng)該全部比較該“位置”中的數(shù)字，而無需轉(zhuǎn)換數(shù)據(jù)類型。接下來輸出 Correctnum 的值，您應(yīng)該得到您需要的內(nèi)容。
神不在的星期二
TA貢獻(xiàn)1963條經(jīng)驗(yàn) 獲得超6個(gè)贊
random = 1234
random = str(random)
#guess = str(input('enter your guess'))
guess = '1222'
correct = 0
for i in range(len(guess)):
if guess[i] == random[i]:
correct += 1
print(correct)
ouput: 2
或者簡單地：
correct = sum(guess[i] == random[i] for i in range(len(guess)))
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