我的目標(biāo)是檢查 cookie 中存儲的“令牌”的值是否與數(shù)據(jù)庫中的 loginTable 表中的值相同。我可以將 cookie 的值保存在變量 $token 中。我遇到的問題在這里 --> if ($row["token"] == $token)。例如$token的值為bm0h8sdigs，行中的值為bm0h8sdigs，但不進(jìn)入if。我也嘗試了 strcmp 函數(shù)，但它不起作用。if(strcmp($row["token"], $token) == 0) 我還嘗試了 $sqlToken = "select * from loginTable where token='" 。$令牌?！?#39;”；但它不起作用?；仫@$令牌；打印我的 cookie 中的內(nèi)容 - bm0h8sdigs<!-- https://github.com/js-cookie/js-cookie This is a library to make handling cookies easier --><script>   var token = Cookies.get('token');</script><?php   $token = "<script>document.write(token)</script>";   $var = 0;   include "connectDB.php";                                   $sqlToken = "SELECT * FROM loginTable";   $resultToken = $mysqli->query($sqlToken);   while($row = $resultToken->fetch_assoc()){        if ($row["token"] == $token){            $var = 1;        }   }   $mysqli->close();                                   if ($var == 1){   //Token found in db   }   else{   //Token not found in db   }?>連接數(shù)據(jù)庫.php<?php    $host = "localhost";    $username = "root";    $password = "usbw";    $database = "test";    $mysqli = new mysqli($host, $username, $password, $database);    $mysqli -> set_charset("utf8");    if ($mysqli->connect_errno) {        echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;     }?>登錄表 - prnt.sc/u7nidnCreate table loginTable(    loginID int AUTO_INCREMENT,    userID int not null,    token varchar(20) not null,    Constraint PK_loginTable Primary Key(loginID),    Constraint FK_loginTable_userID Foreign Key (userID) References usersTable (userID))