所以我無(wú)法弄清楚問(wèn)題出在哪里，就好像我只綁定其中一個(gè)參數(shù)一樣，它可以工作。如果兩者都存在那么它給了我警告：mysqli_stmt::bind_param()：變量數(shù)量與準(zhǔn)備好的語(yǔ)句中的參數(shù)數(shù)量不匹配，并且不產(chǎn)生任何輸出。似乎無(wú)法識(shí)別where子句中的第二個(gè)參數(shù)。如果有人能幫我解決這個(gè)問(wèn)題，謝謝！如果我替換 ? 則查詢(xún)有效 并在 phpMyAdmin 中運(yùn)行。CNIC 應(yīng)該是一個(gè)后值，并且為了測(cè)試目的而被硬編碼。$sql = "SELECT c.cnic, c.name, c.cell_phone, c.address         FROM cheetay_customers as c             INNER JOIN policies as p ON c.CNIC = p.cnic WHERE `c`.`CNIC`= ?                 AND `p`.`partnerName`= ?";if($stmt = $con->prepare($sql)) {     $cnic = 1267890;    $stmt->bind_param("i", $cnic);    $stmt->bind_param("s", $_SESSION['access']);    $stmt->execute();    $stmt->bind_result($cnic, $name,$cell_phone,$address);    while ($stmt->fetch()) {        echo "CNIC: {$cnic}, Name: {$name}, Cell Phone: {$cell_phone}, Address: {$address}";    }} else {    $error = $con->errno . ' ' . $con->error;    echo $error; }