我已經(jīng)審查過這個(gè)問題，但我沒有使用角度。到目前為止，這是我的代碼：<button id='Bx' type="button" onclick='toggleClickedBuz("Bx", "#Bx")'>Bx</button><button id='By' type="button" onclick='toggleClickedBuz("Bx", "#Bx")'>By</button><button id='Bz' type="button" onclick='toggleClickedBuz("Bx", "#Bx")'>Bz</button>我的 JS 是這樣的：function toggleClickedBuz( bizStr , id ) {    if(clickedBusinesses.includes(bizStr)){       // removing duplicate element from that array, dependant on button pressed       clickedBusinesses = clickedBusinesses.filter( cb => cb !== bizStr );       document.getElementById( id ).style.backgroundColor='white';    }else{        // else push it to the array       clickedBusinesses.push(bizStr)       document.getElementById( id ).style.backgroundColor='red';    }    console.log(clickedBusinesses)}