如何通過用戶輸入的數(shù)組應(yīng)用常量數(shù)組并獲得總和？用戶始終輸入 6 位數(shù)字，但常量為 5 位數(shù)字例子[5, 7, 3, 5, 2] 是我要乘以的常量數(shù)組用戶輸入 837465變成 [8, 3,7,4,6,5] （但我希望 5 被忽略）乘以常量數(shù)組（不包括最后一個元素）并得到總和：(8*5)+ (3*7) + (7*3) + (4*5)+ (6*2) = 114const arr = [5, 7, 3, 5, 2];var arr2 = [];var num = parseInt(document.getElementById("yourNumber").value); //input from .htmlvar sum = 0;for (var i = 1; i< num.length; i++){ //var i = 1 b/c user always enters 6 digits, i feel this is wrong? arr2.push(parseInt(num[i])); sum += (arr2[i]*arr[i]);}console.log(sum);
4 回答
一只斗牛犬
TA貢獻1784條經(jīng)驗 獲得超2個贊
嘗試使用const input = '837465'.split('')或準(zhǔn)備好數(shù)組const input = [8, 3, 7, 4, 6, 5]和reduce()方法來求和數(shù)組。當(dāng)原始數(shù)組中有元素時，reduce 就會起作用
const array = [5, 7, 3, 5, 2]
const input = '837465'.split('')
//or
// const input = [8, 3, 7, 4, 6, 5]
const summ = (input) => array.reduce((acum, rec, index) => acum + (rec * input[index]), 0)
console.log(summ(input))
Helenr
TA貢獻1780條經(jīng)驗 獲得超4個贊
for您可以使用清晰的語法of強制執(zhí)行此操作
const arr = [5, 7, 3, 5, 2]
const nums = [8, 3, 7, 4, 6, 5]
let result = 0
for (const [ key, value ] of Object.entries(arr))
result = result + (value * nums[key])
console.log(result) // 114
或者您可以使用聲明式地執(zhí)行此操作Array.prototype.reduce-
const arr = [5, 7, 3, 5, 2]
const nums = [8, 3, 7, 4, 6, 5]
const result =
arr.reduce
( (sum, value, key) => sum + (value * nums[key])
, 0
)
console.log(result) // 114
jeck貓
TA貢獻1909條經(jīng)驗 獲得超7個贊
這是答案（請點擊“運行代碼片段”）
如果您需要任何解釋，或者這不是您要問的，請評論我的答案
function getTotal() {
const arr = [5, 7, 3, 5, 2];
var userNumbers = document.getElementById('yourNumber').value.split('');
var sum = 0;
//itreate over your array case it is short (or a condition to itreate over the shortest one)
for (var i = 0; i < arr.length; i++) {
sum += parseInt(userNumbers[i]) * arr[i];
}
console.log(sum);
document.getElementById('answer').innerHTML ='Answer will be here: '+ sum;
}
<html>
<head>
<title>StackOverFlow 🍗</title>
<link rel="shortcut icon" type="image/x-icon" href="https://image.flaticon.com/icons/png/512/2057/2057586.png" />
</head>
<body>
<h3>Stack Over Flow 🍗</h3>
<input id="yourNumber" type="text" value="837465">
<button onclick="getTotal()">get the answer</button>
<p id="answer">Answer will be here: </p>
</body>
</html>
慕村9548890
TA貢獻1884條經(jīng)驗 獲得超4個贊
以下作品：
const arr = [5, 7, 3, 5, 2];
var num = document.getElementById("yourNumber").value; //input from .html
var sum = 0;
for (var i = 0; i< num.length-1; i++){ //var i = 1 b/c user always enters 6
digits, i feel this is wrong?
sum += (arr[i]*parseInt(num[i]));
}
console.log(sum);
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