我想把這個(gè)序列分成一個(gè) n=3 的列表。codons('agucaccgucautc')# result = ['agu','cac','cgu','cau']# 'tc' is supposed to be ignored as it doesn't equal to n=3我嘗試過以下解決方案；def codons(RNA):     """This functions returns a list of codons present in an RNA sequence"""    # store the length of string    length = len(RNA)    #divide the string in n equal parts    n = 3    temp = 0    chars = int(len(RNA)/3)    #stores the array of string    change = []    #check whether a string can be divided into n equal parts    for i in range(0, length, chars):        part = [RNA[i:i+3] for i in range(0, length, n)];        change.append(part);        return part        if (length % n != 0):            continue但是當(dāng)我嘗試再次運(yùn)行之前的代碼時(shí)，它仍然返回“tc”codons('agucaccgucautc')# result = ['agu', 'cac', 'cgu', 'cau', 'tc']誰能幫我做什么來忽略任何不等于 n=3 或最后一部分“tc”的字符？