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值錯(cuò)誤和零除錯(cuò)誤

Python

慕田峪9158850 2023-10-26 10:19:08

我正在嘗試執(zhí)行計(jì)算 ((x/y) + z) 并解釋 2 個(gè)錯(cuò)誤：ValueError和ZeroDivisionError.但是，我很難理解如何將這兩個(gè)錯(cuò)誤編碼到我的程序中。我想我已經(jīng)ValueError明白了，但還沒有ZeroDivisionError。這是我到目前為止所擁有的。抱歉，有點(diǎn)亂 rn....user_input = (input("Enter three numbers separated by a space: ")).split()x = int(user_input[0])y = int(user_input[1])z = int(user_input[2]) def calculate(x, y, z): '''calculate (x/y)+z''' c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0") return ctry: input_values_str = str(user_input) c = ((x/y) + z) for val in input_values_str: if len(user_input) == 3: print("Correct number of values.") else: print("Incorrect number of values entered.")except ValueError: print(user_input," is not valid input.")except ZeroDivisionError: y = 0 print("Second value cannot be 0")print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))

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4 回答

POPMUISE

TA貢獻(xiàn)1765條經(jīng)驗(yàn) 獲得超5個(gè)贊

恭喜你學(xué)習(xí)了Python！我認(rèn)為你的代碼有點(diǎn)混亂。我將發(fā)布您的版本以及我的一些評(píng)論，然后我將發(fā)布一個(gè)清理版本，我認(rèn)為它可以更好地實(shí)現(xiàn)您想要做的事情。希望它具有指導(dǎo)意義。有更優(yōu)雅的方法可以做到這一點(diǎn)，但我試圖保留你的結(jié)構(gòu)盡可能有意義。

您的代碼：

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

def calculate(x, y, z):

c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0") #Why do you need a ZeroDivisonError check below when you check for Zero here?

return c

try:

input_values_str = str(user_input) # why are you taking an input here? Did you take the input above? And why convert it back into a string?

c = ((x/y) + z)

for val in input_values_str: # Why are you iterating through string? You're basically checking 3 times if the length of your string is 3 characters

if len(user_input) == 3:

print("Correct number of values.")

else:

print("Incorrect number of values entered.")

except ValueError:

print(user_input," is not valid input.")

except ZeroDivisionError:

y = 0 # why set y back to zero in the event oa ZeroDivisonError? Won't that just create a ZeroDivison Error? Might make more sense to get a new input from the user

print("Second value cannot be 0")

print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z))) # if the objective is to only print something, why not do it in the calculate function? Then we can contain your ZeroDivisionError in their and request a new y

我的代碼：

def calculate(x, y, z):

try:

solution = (x/y) + z

print(f"Formula: ({x}/{y}) + {z} = {solution}")

except ZeroDivisionError:

y = int(input("2nd value cannot be a Zero. Please input a new y value: "))

calculate(x, y, z)

try:

user_input = (input("Enter three numbers separated by a space: ")).split()

while len(user_input) != 3:

print("Incorrect number of values entered.")

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

calculate(x, y, z)

except ValueError:

print(user_input," is not valid input.")

反對(duì) 回復(fù) 2023-10-26

HUH函數(shù)

TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超4個(gè)贊

我只是調(diào)整了您的代碼以滿足您的期望，并且易于理解。

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

try:

c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0")

except ValueError:

print(user_input," is not valid input.")

print("Formula: ({}/{}) + {} = {}".format(x, y, z, c))

反對(duì) 回復(fù) 2023-10-26

小唯快跑啊

TA貢獻(xiàn)1863條經(jīng)驗(yàn) 獲得超2個(gè)贊

我根本不明白為什么你需要 try/ except/ except 塊。y=0您已經(jīng)在您的方法中進(jìn)行了檢查calculate，并且您已經(jīng)知道您有有效的輸入，否則和split強(qiáng)制轉(zhuǎn)換int()將會(huì)失敗。其中的循環(huán)for一遍又一遍地打印相同的輸出字符串。如果你把所有這些都去掉，你的代碼似乎工作正常

try:

file_name = open('/tmp/data.txt', 'r')

except FileNotFoundError:

print("File could not be found. Please check spelling of file name!")

sys.exit()

#Read lines in file

Lines = file_name.read().splitlines()

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

def calculate(x, y, z):

'''calculate (x/y)+z'''

c = ((x / y) + z) if y != 0 else print("Second input value cannot be 0")

return c

print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))

反對(duì) 回復(fù) 2023-10-26

藍(lán)山帝景

TA貢獻(xiàn)1843條經(jīng)驗(yàn) 獲得超7個(gè)贊

您引發(fā)了一個(gè)異常來(lái)查看 y == 0 是否，但第一個(gè)值 (x) 也不能為 0。并且您需要將 2 個(gè) if 語(yǔ)句放在 c = ... 之前

嘗試這個(gè)：

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

def calculate(x, y, z):

'''calculate (x/y)+z'''

if y == 0 or x == y:

print("Invalid Input")

else:

c = ((x/y) + z)

return c

try:

input_values_str = str(user_input)

c = ((x/y) + z)

for val in input_values_str:

if len(user_input) == 3:

print("Correct number of values.")

else:

print("Incorrect number of values entered.")

except ValueError:

print(user_input," is not valid input.")

except ZeroDivisionError:

y = 0

x = 0

print("Second value cannot be 0. First Value cannot be 0")

print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))

反對(duì) 回復(fù) 2023-10-26

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值錯(cuò)誤和零除錯(cuò)誤

值錯(cuò)誤和零除錯(cuò)誤

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