Actual i get
Array (
[person1] => Array
(
[stage1] => 4
[stage2] => 4
[stage3] => 4
[stage4] => 4
[stage5] => 2
)
[person2] => Array
(
[stage3] => 1
)
[person3] => Array
(
[stage1] => 2
[stage2] => 1
[stage4] => 1
[stage5] => 2
)
)1)這里有5個(gè)階段stage1,stage2...stage52）他們是3個(gè)用戶 person1 person2 person3有些人沒有階段，請?jiān)谠撾A段保持為零或?yàn)榭諏⒋藬?shù)組隱藏到表中，如下圖所示，請幫助我https://i.stack.imgur.com/ccJLg.png
1 回答
臨摹微笑
TA貢獻(xiàn)1982條經(jīng)驗(yàn) 獲得超2個(gè)贊
首先，如果事先不知道并且可能是動(dòng)態(tài)的，則需要找到所有階段。如果有的話，您可以通過迭代數(shù)據(jù)來構(gòu)建表。
<?php
$data = [
'person1' => [
'stage1' => 4,
'stage2' => 4,
'stage3' => 4,
'stage4' => 4,
'stage5' => 2,
],
'person2' => [
'stage3' => 1,
],
'person3' => [
'stage1' => 2,
'stage2' => 1,
'stage4' => 1,
'stage5' => 2,
],
];
$stages = [];
foreach ($data as $person) {
foreach ($person as $stage => $number) {
if (!in_array($stage, $stages)) {
$stages[] = $stage;
}
}
}
var_dump($stages);
?>
<table>
<th>person</th>
<?php foreach ($stages as $stage): ?>
<th><?php echo $stage; ?></th>
<?php endforeach ?>
<?php foreach ($data as $personName => $person): ?>
<tr>
<td><?php echo $personName; ?></td>
<?php foreach ($stages as $stage): ?>
<td><?php echo $person[$stage] ?? 0; ?></td>
<?php endforeach; ?>
</tr>
<?php endforeach; ?>
</table>
結(jié)果：
array(5) { [0]=> string(6) "stage1" [1]=> string(6) "stage2" [2]=> string(6) "stage3" [3]=> string(6) "stage4" [4]=> string(6) "stage5" }
person stage1 stage2 stage3 stage4 stage5
person1 4 4 4 4 2
person2 0 0 1 0 0
person3 2 1 0 1 2
- 1 回答
- 0 關(guān)注
- 126 瀏覽
添加回答
舉報(bào)
0/150
提交
取消