例如，我有這個數(shù)組：$bills = array( array("bill_id"=>"1", "product_id"=>"1", "total"=>"10"), array("bill_id"=>"2", "product_id"=>"2", "total"=>"20"), array("bill_id"=>"3", "product_id"=>"1", "total"=>"30"), array("bill_id"=>"4", "product_id"=>"1", "total"=>"40"), array("bill_id"=>"5", "product_id"=>"2", "total"=>"50") );我們需要將每個產(chǎn)品的總計(jì)添加到一個數(shù)組中，即從上面的數(shù)組生成以下數(shù)組的最佳干凈快速方法是什么： $products = array( array("product_id"=>"1", "total"=>"80"), array("product_id"=>"2", "total"=>"70") );
2 回答
白衣非少年
TA貢獻(xiàn)1155條經(jīng)驗(yàn) 獲得超0個贊
求和的最快方法是索引數(shù)組，像這樣
$products = array();
foreach ($bills as $bill) {
$key = $bill['product_id'];
if (isset($products[$key])) {
$products[$key]['total'] += $bill['total'];
} else {
$products[$key] = $bill;
}
}
var_dump($products);
輸出
array(2) {
[1]=>
array(3) {
["bill_id"]=>
string(1) "1"
["product_id"]=>
string(1) "1"
["total"]=>
int(80)
}
[2]=>
array(3) {
["bill_id"]=>
string(1) "2"
["product_id"]=>
string(1) "2"
["total"]=>
int(70)
}
}
瀏覽發(fā)票清單
foreach($products as $key=>$bill) {
var_dump($bill);
}
守著一只汪
TA貢獻(xiàn)1872條經(jīng)驗(yàn) 獲得超4個贊
最簡單的方法是單遍循環(huán)。
$byProduct = [];
foreach($bills as $bill)
{
$key = $bill['product_id'];
if (!isset($byProduct[$key])) {
$byProduct[$key] = [
'product_id' => $key,
'total' => 0
];
}
$byProduct[$key]['total'] += $bill['total'];
}
結(jié)果var_dump($byProduct)：
array(2) {
[1] =>
array(2) {
'product_id' =>
string(1) "1"
'total' =>
int(80)
}
[2] =>
array(2) {
'product_id' =>
string(1) "2"
'total' =>
int(70)
}
}
另一種方法是使用array_walk，但在復(fù)雜性方面幾乎相同：
$byProduct = [];
array_walk($bills, function(&$bill) use (&$byProduct) {
$key = $bill['product_id'];
if (!isset($byProduct[$key])) {
$byProduct[$key] = [
'product_id' => $key,
'total' => 0
];
}
$byProduct[$key]['total'] += $bill['total'];
});
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