您可以像這樣使用自定義查詢<?php$authorID = get_the_author_meta('ID');$args = array( 'post_type' => 'product', 'post_status' => 'publish' 'posts_per_page' => 12, 'product_cat' => 'pants' 'author' => $authorID);$loop = new WP_Query( $args );?> <div class="author_products"> <?php if ( $loop->have_posts() ) { ?> <ul class="author_pubproducts"> <?php while ( $loop->have_posts() ) : $loop->the_post(); woocommerce_get_template_part( 'content', 'product' ); endwhile; ?> </ul> <?php } else { echo __( 'No products found', 'textdomain' ); } wp_reset_postdata(); ?>希望能成功
2 回答
狐的傳說(shuō)
TA貢獻(xiàn)1804條經(jīng)驗(yàn) 獲得超3個(gè)贊
這就是我要做的：
// I take first element of array as a source for indexes
foreach ($myArray[0] as $index => $item) {
// next I extract all elements from all subarrays under current `$index`
$values = array_column($myArray, $index);
// then I filter values to remove nulls.
// This also removes 0, empty arrays, false,
// so maybe you should change filter process
$values_filtered = array_filter($values);
// if number of filtered items is same as in original array - no nulls found
if (count($values_filtered) === count($values)) {
echo $index;
// optionally
// break;
}
}
一只名叫tom的貓
TA貢獻(xiàn)1906條經(jīng)驗(yàn) 獲得超3個(gè)贊
盡管有一個(gè)公認(rèn)的答案，但我想我會(huì)分享一種使用 Laravel 集合來(lái)做到這一點(diǎn)的方法。
$uniqueKeysWithValues = collect($myArray)->map(function($item){
return array_keys( collect($item)->filter()->toArray() ); //filter will remove all null
})->flatten()->unique();
這種方法將為您提供所有包含值的鍵，即使兩個(gè)鍵中都有值。
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