我侄女在學(xué)校做作業(yè)時(shí)問我這個(gè)問題，我不知道該怎么做。老師要求他們?cè)?java 中使用 3 個(gè) for 循環(huán)打印以下模式：1******12*****123****1234***12345**123456*1234567請(qǐng)幫忙。謝謝！
3 回答
慕蓋茨4494581
TA貢獻(xiàn)1850條經(jīng)驗(yàn) 獲得超11個(gè)贊
這曾經(jīng)是我的家庭作業(yè)
代碼
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
System.out.println("");
}
將會(huì)呈現(xiàn)
1
12
123
1234
12345
123456
1234567
和
for (int i = 1; i <= 7; i++) {
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
將會(huì)呈現(xiàn)
******
*****
****
***
**
*
最終的
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
將會(huì)呈現(xiàn)
1******
12*****
123****
1234***
12345**
123456*
1234567
回首憶惘然
TA貢獻(xiàn)1847條經(jīng)驗(yàn) 獲得超11個(gè)贊
public static void printPattern(int n) {
for(int i=0; i<n; i++) {
for(int k=1; k<=i+1; k++) {
System.out.print(k);
}
for(int j=i+1; j<n; j++) {
System.out.print("*");
}
System.out.println("");
}
}
MYYA
TA貢獻(xiàn)1868條經(jīng)驗(yàn) 獲得超4個(gè)贊
Are you sure question has been asked to solve by using 3 for loops?
As it is better to use less loop as much as we can. Secondly there is no requirement in problem to use third loop. you can find the desired result by using two loops:
public class Main
{
public static void main(String[] args) {
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= 7; j++) {
if (j <= i) {
System.out.print(j);
}
else
{
System.out.print("*");
}
}
System.out.println("\n");
}
}
}
output will be:
1******
12*****
123****
1234***
12345**
123456*
1234567
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