這是我的代碼：import timefrom selenium import webdriverfrom selenium.webdriver.common.keys import Keys# loading the webpagebrowser = webdriver.Chrome()browser.get("https://instagram.com")time.sleep(1)# finding essential requirementsuser_name = browser.find_element_by_name("username")password = browser.find_element_by_name("password")login_button = browser.find_element_by_xpath("//button [@type = 'submit']")# filling out the user name boxuser_name.click()user_name.clear()user_name.send_keys("username")# filling out the password boxpassword.click()password.clear()password.send_keys("password")# clicking on the login buttonlogin_button.click()time.sleep(3)# information save permission denialnot_now_button = browser.find_element_by_xpath("//button [@class = 'sqdOP yWX7d    y3zKF     ']")not_now_button.click()time.sleep(3)# notification permission denialnot_now_button_2 = browser.find_element_by_xpath("//button [@class = 'aOOlW   HoLwm ']")not_now_button_2.click()time.sleep(3)# finding search box and searching + going to the pagesearch_box = browser.find_element_by_xpath('//input [@placeholder="Search"]')search_box.send_keys("sb else's page")time.sleep(3)search_box.send_keys(Keys.RETURN)search_box.send_keys(Keys.RETURN)time.sleep(3)# opening ((followers)) listfollowers = browser.find_element_by_xpath('//a [@class="-nal3 "]')followers.click()time.sleep(10)# following each followerfollower = browser.find_elements_by_xpath('//button [@class="sqdOP  L3NKy   y3zKF     "]')browser.close()在這段代碼中，我通常模擬一個普通人跟隨另一個人的行為。我想關(guān)注頁面的每個關(guān)注者。我整天都在想；但找不到任何算法。有一些好主意，但剛剛意識到我不知道如何向下滾動到列表末尾以獲取整個列表。你能幫我嗎？（如果您不明白我的意思，請嘗試運(yùn)行代碼，然后提取關(guān)注者列表。）