如果兩個數(shù)組包含相同數(shù)量的項目，那么您可以使用普通的 for 循環(huán)來訪問具有相同索引的每個項目，如下所示 -let home_team = ["A", "B", "C"];let away_team = ["D", "E", "F"];for(let i=0; i<home_team.length; i++){  console.log(`${home_team[i]} VS ${away_team[i]}`);}展開片段或者，您也可以在 for 循環(huán)中使用多個計數(shù)器，如下所示（盡管您現(xiàn)在不需要這個 -let home_team = ["A", "B", "C"];let away_team = ["D", "E", "F"];for(let i=0,j=2; i<home_team.length; i++, j--){  console.log(`${home_team[i]} VS ${away_team[j]}`);}