2 回答

TA貢獻(xiàn)1856條經(jīng)驗(yàn) 獲得超5個(gè)贊
只需使用索引 for 循環(huán)
for(let i = 0;i < home_team.length; i++) { console.log(home_team[i] + "VS" + away_team[i]); }
您還可以使用forEach
home_team.forEach((item, index) => console.log(item + "VS" + away_team[index]));

TA貢獻(xiàn)1829條經(jīng)驗(yàn) 獲得超9個(gè)贊
如果兩個(gè)數(shù)組包含相同數(shù)量的項(xiàng)目,那么您可以使用普通的 for 循環(huán)來(lái)訪問(wèn)具有相同索引的每個(gè)項(xiàng)目,如下所示 -
let home_team = ["A", "B", "C"];
let away_team = ["D", "E", "F"];
for(let i=0; i<home_team.length; i++){
console.log(`${home_team[i]} VS ${away_team[i]}`);
}
或者,您也可以在 for 循環(huán)中使用多個(gè)計(jì)數(shù)器,如下所示(盡管您現(xiàn)在不需要這個(gè) -
let home_team = ["A", "B", "C"];
let away_team = ["D", "E", "F"];
for(let i=0,j=2; i<home_team.length; i++, j--){
console.log(`${home_team[i]} VS ${away_team[j]}`);
}
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