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在Android中，我如何按日期對(duì)數(shù)組項(xiàng)進(jìn)行分組？

Java

婷婷同學(xué)_ 2023-09-27 16:47:35

對(duì)象array的 Statement:[ { "date": "12-09-19 11:02:47", "Country": "Bangladesh", "Profession": "X", "Salary": "100", }, { "date": "12-09-19 11:02:47", "Country": "Bangladesh", "Profession": "Y", "Salary": "101", }, { "date": "12-09-19 11:02:47", "Country": "Bangladesh", "Profession": "Z", "Salary": "102", }, { "date": "11-09-19 11:02:47", "Country": "India", "Profession": "I", "Salary": "103", }, { "date": "11-09-19 11:02:47", "Country": "India", "Profession": "J", "Salary": "104", }, { "date": "10-09-19 11:02:47", "Country": "Nepal", "Profession": "N", "Salary": "105", }, { "date": "10-09-19 11:02:47", "Country": "Nepal", "Profession": "M", "Salary": "106", } ]我正在嘗試創(chuàng)建一個(gè)新的array，它將創(chuàng)建一個(gè)object包含每個(gè)日期（作為鍵）和同一object.新數(shù)組應(yīng)如下所示： "10-09-19": [ { "Country": "Nepal", "Profession": "M", "Salary": "106", }, { "Country": "Nepal", "Profession": "N", "Salary": "105", } ], "11-09-19": [{ "Country": "India", "Profession": "J", "Salary": "104", }, { "Country": "India", "Profession": "I", "Salary": "103", } ], "12-09-19": [{ "Country": "Bangladesh", "Profession": "x", "Salary": "104", }, { "Country": "Bangladesh", "Profession": "y", "Salary": "103", }, { "Country": "Bangladesh", "Profession": "z", "Salary": "102", } ]

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4 回答

肥皂起泡泡

TA貢獻(xiàn)1829條經(jīng)驗(yàn) 獲得超6個(gè)贊

使用 hashmap 明智地存儲(chǔ)數(shù)據(jù)。哈希圖的鍵將是日期。這是我的代碼，它可能會(huì)幫助您理解邏輯。

var sortedList= HashMap<String, MutableList<Model>>() // create hashmap to store data

var temp: MutableList<Model>? = ArrayList<Model>()

for (item in currentList!!) {

temp = sortedList?.get(item.date.split(" ").get(0)) // get date and remove timing

if (temp != null) //if this is not null it mean this contain items

temp.add(item)

else {

temp = ArrayList<Model>() //if this is null it means this is new data or new data

temp.add(item)

}

sortedList?.put(item.date.split(" ").get(0), temp)

}

我的代碼是 kotlin 的，對(duì)此深表歉意?？鞓?lè)編碼。

反對(duì) 回復(fù) 2023-09-27

慕村225694

TA貢獻(xiàn)1880條經(jīng)驗(yàn) 獲得超4個(gè)贊

我假設(shè)你提供的都是JSON字符串（但它們看起來(lái)無(wú)效），那么你可以按如下方式實(shí)現(xiàn)轉(zhuǎn)換：

ObjectMapper mapper = new ObjectMapper();

ObjectNode root = (ObjectNode) mapper.readTree(jsonStr);

ObjectNode rootNew = mapper.createObjectNode();

for (int i = 0; i < root.get("Statement").size(); i++) {

String date = root.get("Statement").get(i).get("date").asText().split(" ")[0];

ObjectNode node = (ObjectNode) ((ObjectNode) root.get("Statement").get(i));

node.remove("date");

if (rootNew.has(date)) {

((ArrayNode) rootNew.get(date)).add(node);

} else {

rootNew.put(date, mapper.createArrayNode().add(node));

}

System.out.println(rootNew.toString());

控制臺(tái)輸出：

{

"12-09-19":[

{

"Country":"Bangladesh",

"Profession":"X",

"Salary":"100"

},

{

"Country":"Bangladesh",

"Profession":"Y",

"Salary":"101"

},

{

"Country":"Bangladesh",

"Profession":"Z",

"Salary":"102"

}

],

"11-09-19":[

{

"Country":"India",

"Profession":"I",

"Salary":"103"

},

{

"Country":"India",

"Profession":"J",

"Salary":"104"

}

],

"10-09-19":[

{

"Country":"Nepal",

"Profession":"N",

"Salary":"105"

},

{

"Country":"Nepal",

"Profession":"M",

"Salary":"106"

}

]

}

反對(duì) 回復(fù) 2023-09-27

拉丁的傳說(shuō)

TA貢獻(xiàn)1789條經(jīng)驗(yàn) 獲得超8個(gè)贊

首先感謝各位回答我的問(wèn)題。我后來(lái)找到了一個(gè)解決方案。我想我應(yīng)該與大家分享這一點(diǎn)。

JSONArray statementArray = response.getJSONArray("statement");

Map<String, List<String>> map= new HashMap<String, List<String>>();

for(int i = 0; i < statementArray.length(); i ++) {

JSONObject mJsonObjectStatement = statementArray.getJSONObject(i);

String date= mJsonObjectStatement.getString("date").split(" ")[0];

List<String> valSet = new ArrayList<String>();

valSet.add(0,mJsonObjectStatement.getString("Country"));

valSet.add(1,mJsonObjectStatement.getString("Profession"));

valSet.add(2,mJsonObjectStatement.getString("Salary"));

map.put(date,valSet);

}

for (Map.Entry<String, List<String>> entry : transactionReportMap.entrySet()) {

String key = entry.getKey();

List<String> values = entry.getValue();

Log.e("Key = " , key);

Log.e("Values = " , values + "n");

}

Log.e("Result:",map.toString());

上述解決方案沒(méi)有提供相同的結(jié)果，但它達(dá)到了我的目的。

我找到的另一個(gè)解決方案

JSONArray statementArray = response.getJSONArray("statement");

ObjectMapper mapper = new ObjectMapper();

Map<String, List<String>> map= new HashMap<String, List<String>>();

for(int i = 0; i < statementArray.length(); i ++) {

JSONObject mJsonObjectStatement = statementArray.getJSONObject(i);

String date= mJsonObjectStatement.getString("date").split(" ")[0];

if (transactionReportMap.containsKey(date)) {

map.get(date).add(date);

} else {

ArrayList<String> infoList = new ArrayList<String>();

infoList.add(mJsonObjectStatement.getString("Country"));

infoList.add(mJsonObjectStatement.getString("Profession"));

infoList.add(mJsonObjectStatement.getString("Salary"));

map.put(date, infoList);

}

StringWriter result = new StringWriter();

try {

mapper.writeValue(result, map);

} catch (IOException e) {

e.printStackTrace();

}

Log.e("Result: ",result+"");

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開(kāi)心每一天1111

TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超13個(gè)贊

對(duì)于這個(gè)問(wèn)題來(lái)說(shuō)可能為時(shí)已晚，但我正在分享我的答案。

//Define an empty hash map

Map<String, JSONObject> finalMap = map;

for (JSONObject object : Statement) {

String key = object.getString("date");

//Split the date from date time

if (key.contains(" ")) {

key = key.split(" ")[0];

}

if (finalMap.containsKey(key)) {

JSONArray list = finalMap.get(key);

list.put(student);

} else {

JSONArray list = new JSONArray();

list.put(object);

finalMap.put(key, list);

}

最后，您可以將哈希映射轉(zhuǎn)換為您需要的任何類型。

反對(duì) 回復(fù) 2023-09-27

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在Android中，我如何按日期對(duì)數(shù)組項(xiàng)進(jìn)行分組？

在Android中，我如何按日期對(duì)數(shù)組項(xiàng)進(jìn)行分組？