我將隨機(jī)進(jìn)行一個(gè)有趣的測(cè)驗(yàn)，包含 3 個(gè)問(wèn)題，并提供 3 次猜測(cè)的機(jī)會(huì)。在我嘗試執(zhí)行后，我嘗試了正確的答案，但繼續(xù)循環(huán)并告訴我的答案不正確并且無(wú)法停止循環(huán)，我不知道為什么......有人可以幫我看一下嗎？q1 = 'What can one catch that is not thrown?'a1 = 'A cold'q2 = 'If you had only one match and entered a dark room containing an oil lamp, some kindling wood, and a newspaper, which would you light first?'a2= 'The match'q3 = 'Some months have 31 days, others have 30 days, but how many have 28 days?'a3= 'All the months'import randomquizzes = [q1, q2, q3] #catagorise to quizzesfor answer in random.choice(quizzes): guesses = 3 # limits to 3 guesses random.choice(quizzes) asking = input('Your Answer is?\n') if quizzes == q1 and asking == 'A cold': print( 'Bingo!!') break elif quizzes == q2 and asking == 'The match': print( 'Bingo!!') break elif quizzes == q3 and asking == 'All the months': print( 'Bingo!!') break elif guesses == 0: print( 'Sorry, you are reached the maximum guesses. Bye~now~') else: guesses -= 1 #reducing the max. guesses of 3 to 2 to 1 print( "Sorry, it's incorrect.") result = asking
2 回答
臨摹微笑
TA貢獻(xiàn)1982條經(jīng)驗(yàn) 獲得超2個(gè)贊
該行for answer in random.choice(quizzes)實(shí)際上獲取一個(gè)隨機(jī)測(cè)驗(yàn)字符串，然后迭代字符串中的每個(gè)字符；這就是為什么循環(huán)看起來(lái)沒(méi)有停止，因?yàn)樗捻?xiàng)目比您預(yù)期的要多。
最初在循環(huán)中的行random.choice(quizzes), 不執(zhí)行任何操作；該random.choice()函數(shù)從列表中返回一個(gè)隨機(jī)項(xiàng)目。如果您不對(duì)返回值執(zhí)行任何操作（例如打印它），那么什么也不會(huì)發(fā)生。
您原來(lái)的行if quizzes == q1 and asking == 'A cold':不會(huì)起作用，因?yàn)閝uizzes是您的測(cè)驗(yàn)列表，所以檢查quizzes == q1將始終是False。在我的代碼中，由于我循環(huán)通過(guò)quizzesvia for quiz in quizzes，這意味著quiz在我的代碼中是來(lái)自 的測(cè)驗(yàn)字符串quizzes，因此當(dāng)我quiz == q1這樣做時(shí)，可以正確地將當(dāng)前quiz與q1,q2或進(jìn)行比較q3。
a1我注意到您在、a2和中定義了答案a3，因此您可以簡(jiǎn)化代碼并使用它們進(jìn)行比較asking，例如asking == a1代替asking == 'A cold'。
import random
quizzes = [q1, q2, q3] #catagorise to quizzes
random.shuffle(quizzes) # randomize the quiz order
for quiz in quizzes: # loop through the list of quizzes
guesses = 3 # limits to 3 guesses
print(quiz) # prompt the user with the quiz question
while True: # keep asking for answers until guesses run out, or the user gets a correct answer
asking = input('Your Answer is?\n')
if quiz == q1 and asking == a1:
print( 'Bingo!!')
break
elif quiz == q2 and asking == a2:
print( 'Bingo!!')
break
elif quiz == q3 and asking == a3:
print( 'Bingo!!')
break
elif guesses == 0:
print( 'Sorry, you are reached the maximum guesses. Bye~now~')
break
else:
guesses -= 1 #reducing the max. guesses of 3 to 2 to 1
print( "Sorry, it's incorrect.")
紅糖糍粑
TA貢獻(xiàn)1815條經(jīng)驗(yàn) 獲得超6個(gè)贊
你的問(wèn)題是猜測(cè)的位置?，F(xiàn)在它在你的 for 循環(huán)內(nèi)。將其放在 for 循環(huán)之外，它應(yīng)該可以工作。
您還應(yīng)該看看您的
elif guesses == 0:
現(xiàn)在，即使猜測(cè)次數(shù)為 0，玩家也能猜出。它可能應(yīng)該是<=1。
您的代碼將按照您想要的方式運(yùn)行，如下所示：
q1 = 'What can one catch that is not thrown?'
a1 = 'A cold'
q2 = 'If you had only one match and entered a dark room containing an oil lamp, some kindling wood, and a newspaper, which would you light first?'
a2= 'The match'
q3 = 'Some months have 31 days, others have 30 days, but how many have 28 days?'
a3= 'All the months'
import random
quizzes = [q1, q2, q3] #catagorise to quizzes
guesses = 3
for answer in random.choice(quizzes):
# limits to 3 guesses
random.choice(quizzes)
asking = input('Your Answer is?\n')
if quizzes == q1 and asking == 'A cold':
print( 'Bingo!!')
break
elif quizzes == q2 and asking == 'The match':
print( 'Bingo!!')
break
elif quizzes == q3 and asking == 'All the months':
print( 'Bingo!!')
break
elif guesses <=1:
print( 'Sorry, you are reached the maximum guesses. Bye~now~')
exit()
else:
guesses -= 1 #reducing the max. guesses of 3 to 2 to 1
print( "Sorry, it's incorrect.")
result = asking
添加回答
舉報(bào)
0/150
提交
取消