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Javascript 重新格式化或?qū)ο髷?shù)組映射到新對象的新數(shù)組？就像重新格式化它一樣

JavaScript

暮色呼如 2023-09-21 16:56:06

我對數(shù)組和對象很陌生，所以我一整天都在做這個任務(wù)，我有一個 JSON 文件或數(shù)組 lang (JavaScript)，我也在 StackOverflow 上搜索，但不能很好地理解它們：[ { "date": "1959:01", this"1": 138.89, "2": 139.39, "3": 139.74, "4": 139.69, "5": 140.68, "6": 141.17 }, { "date": "1959:07", "1": 141.7, "2": 141.9, "3": 141.01, "4": 140.47, "5": 140.38, "6": 139.95 }, { "date": "1960:01", "1": 139.98, "2": 139.87, "3": 139.75, "4": 139.56, "5": 139.61, "6": 139.58 }, { "date": "1960:07", "1": 140.18, "2": 141.31, "3": 141.18, "4": 140.92, "5": 140.86, "6": 140.69 }, { "date": "1961:01", "1": 141.06, "2": 141.6, "3": 141.87, "4": 142.13, "5": 142.66, "6": 142.88 }, { "date": "1961:07", "1": 142.92, "2": 143.49, "3": 143.78, "4": 144.14, "5": 144.76, "6": 145.2 }, { "date": "1962:01", "1": 145.24, "2": 145.66, "3": 145.96, "4": 146.4, "5": 146.84, "6": 146.58 }, { "date": "1962:07", "1": 146.46, "2": 146.57, "3": 146.3, "4": 146.71, "5": 147.29, "6": 147.82 }, { "date": "1963:01", "1": 148.26, "2": 148.9, "3": 149.17, "4": 149.7, "5": 150.39, "6": 150.43 }, { "date": "1963:07", "1": 151.34, "2": 151.78, "3": 151.98, "4": 152.55, "5": 153.65, "6": 153.29 }, { "date": "1964:01", "1": 153.74, "2": 154.31, "3": 154.48, "4": 154.77, "5": 155.33, "6": 155.62 }, { "date": "1964:07", "1": 156.8, "2": 157.82, "3": 158.75, "4": 159.24, "5": 159.96, "6": 160.3 }, { "date": "1965:01", "1": 160.71, "2": 160.94, "3": 161.47, "4": 162.03, "5": 161.7, "6": 162.19 }, { "date": "1965:07", "1": 163.05, "2": 163.68, "3": 164.85, "4": 165.97, "5": 166.71, "6": 167.85 }, { "date": "1966:01", "1": 169.08, "2": 169.62, "3": 170.51, "4": 171.81, "5": 171.33, "6": 171.57 }, { "date": "1966:07", "1": 170.31, "2": 170.81, "3": 171.97, "4": 171.16, "5": 171.38, "6": 172.03 }]這些就像公司在指定年數(shù)內(nèi)的收入，例如 1959:01 年初，從 1 到 6 是該年的前 6 個月，同年 1956:07 但“:07”中的差異是值同年最后 6 個月（1 到 6）的數(shù)據(jù)，所以我想每個月輸出如下，其中包含它的值和年份，請使用最容易理解的代碼。 [ {"year": 1996,"month": 1,"value": 88512.12 }, {"year": 1996,"month": 2,"value": 71212.12 },

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3 回答

慕村225694

TA貢獻(xiàn)1880條經(jīng)驗(yàn) 獲得超4個贊

如果我正確理解你的問題，那么你可以這樣做：

const financialResults = [

{ "date": "1959:01", "1": 138.89, "2": 139.39, "3": 139.74, "4": 139.69, "5": 140.68, "6": 141.17 },

{ "date": "1959:07", "1": 141.7, "2": 141.9, "3": 141.01, "4": 140.47, "5": 140.38, "6": 139.95 },

{ "date": "1960:01", "1": 139.98, "2": 139.87, "3": 139.75, "4": 139.56, "5": 139.61, "6": 139.58 },

{ "date": "1960:07", "1": 140.18, "2": 141.31, "3": 141.18, "4": 140.92, "5": 140.86, "6": 140.69 },

{ "date": "1961:01", "1": 141.06, "2": 141.6, "3": 141.87, "4": 142.13, "5": 142.66, "6": 142.88 },

{ "date": "1961:07", "1": 142.92, "2": 143.49, "3": 143.78, "4": 144.14, "5": 144.76, "6": 145.2 },

{ "date": "1962:01", "1": 145.24, "2": 145.66, "3": 145.96, "4": 146.4, "5": 146.84, "6": 146.58 },

{ "date": "1962:07", "1": 146.46, "2": 146.57, "3": 146.3, "4": 146.71, "5": 147.29, "6": 147.82 },

{ "date": "1963:01", "1": 148.26, "2": 148.9, "3": 149.17, "4": 149.7, "5": 150.39, "6": 150.43 },

{ "date": "1963:07", "1": 151.34, "2": 151.78, "3": 151.98, "4": 152.55, "5": 153.65, "6": 153.29 },

{ "date": "1964:01", "1": 153.74, "2": 154.31, "3": 154.48, "4": 154.77, "5": 155.33, "6": 155.62 },

{ "date": "1964:07", "1": 156.8, "2": 157.82, "3": 158.75, "4": 159.24, "5": 159.96, "6": 160.3 },

{ "date": "1965:01", "1": 160.71, "2": 160.94, "3": 161.47, "4": 162.03, "5": 161.7, "6": 162.19 },

{ "date": "1965:07", "1": 163.05, "2": 163.68, "3": 164.85, "4": 165.97, "5": 166.71, "6": 167.85 },

{ "date": "1966:01", "1": 169.08, "2": 169.62, "3": 170.51, "4": 171.81, "5": 171.33, "6": 171.57 },

{ "date": "1966:07", "1": 170.31, "2": 170.81, "3": 171.97, "4": 171.16, "5": 171.38, "6": 172.03 }

]

// Extract semester and year: assign 2 if entry corresponds to second semester or 1 if it corresponds to the first

// semester in the year

const extractYearAndSemester = date => ({ year: date.split(":")[0], semester: date.split(":")[1] > 6 ? 2 : 1 })

// For each entry, return an array of objects with the desired properties

// Finally, flatten the array, so you don't end up with an array of arrays

const formatResults = arr => arr.

flatMap(entry => {

const { year, semester } = extractYearAndSemester(entry.date)

let semesterResults = []

for (let key in entry) {

if (parseInt(key)) {

semesterResults.push({

year,

month: semester === 1 ? parseInt(key) : parseInt(key) + 6,

value: entry[key]

})

}

return semesterResults

})

console.log(formatResults(financialResults))

反對回復(fù) 2023-09-21

米脂

TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超3個贊

嘗試循環(huán)遍歷數(shù)據(jù)并解析每個記錄的屬性，如下所示。在外循環(huán)結(jié)束時，您將在 MonthData 變量中獲得具有所需格式的數(shù)據(jù)；

var data = [

{ "date": "1959:01", "1": 138.89, "2": 139.39, "3": 139.74, "4": 139.69, "5": 140.68, "6": 141.17 },

{ "date": "1959:07", "1": 141.7, "2": 141.9, "3": 141.01, "4": 140.47, "5": 140.38, "6": 139.95 },

];

var monthData = [];

for (let index = 0; index < data.length; index++) {

var item =data[index];

var dateArray = item.date.split(":");

var year = dateArray[0];

var baseMonth = Number(dateArray[1]);

for (var key in item) {

if (item.hasOwnProperty(key)) {

var val = item[key];

if (String(val).indexOf(":")== -1) {

monthData.push({

year:year ,

month: baseMonth-1 + Number(key),

value: val,

});

}

反對回復(fù) 2023-09-21

慕工程0101907

TA貢獻(xiàn)1887條經(jīng)驗(yàn) 獲得超5個贊

閱讀有關(guān)此軟件包的信息，它將讓您的生活更輕松：use of _map - Lodash

反對回復(fù) 2023-09-21

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Javascript 重新格式化或?qū)ο髷?shù)組映射到新對象的新數(shù)組？就像重新格式化它一樣

Javascript 重新格式化或?qū)ο髷?shù)組映射到新對象的新數(shù)組？就像重新格式化它一樣

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Javascript 重新格式化或?qū)ο髷?shù)組映射到新對象的新數(shù)組？就像重新格式化它一樣

Javascript 重新格式化或?qū)ο髷?shù)組映射到新對象的新數(shù)組？就像重新格式化它一樣