我有一個 Java Rest API Post 方法，該方法發(fā)送圖像（InputStream）作為參數(shù)，并且我必須將其保存在 Oracle 中的 blob 列中。我需要獲取此InputStream的完整路徑（真實路徑）以將此圖像保存在數(shù)據(jù)庫中。我的代碼如下。@POST@Path("/upload")@Consumes(MediaType.MULTIPART_FORM_DATA)public Response uploadFile( @FormDataParam("file") InputStream uploadedInputStream, @FormDataParam("file") FormDataContentDisposition fileDetail) {String UPLOAD_FOLDER = "c:/uploadedFiles/"; // my rest api does not have this file, how to get at runtime? String uploadedFileLocation = UPLOAD_FOLDER + fileDetail.getFileName(); // this line is ok我想做這樣的事情：String UPLOAD_FOLDER = uploadedInputStream.getRealPathName();或者String UPLOAD_FOLDER = fileDetail.getRealPathName();
1 回答
拉莫斯之舞
TA貢獻1820條經(jīng)驗 獲得超10個贊
我通過將輸入流轉(zhuǎn)換為字節(jié)數(shù)組解決了這個問題。我將 byte[] 轉(zhuǎn)發(fā)給數(shù)據(jù)庫持久化方法。我的代碼如下：
public byte[] toByteArray(InputStream is) throws IOException{
ByteArrayOutputStream baus = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int len;
while((len= is.read(buffer)) != -1){
baus.write(buffer, 0, len);
}
return baus.toByteArray();
}
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
@FormDataParam("file") InputStream uploadedInputStream,
@FormDataParam("file") FormDataContentDisposition fileDetail) {
...
byte[] b = toByteArray(uploadedInputStream);
business.saveUploadedFileInDatabase(b);
...
}
public boolean uploadFile(byte[] b) throws SQLException, IOException{
...
PreparedStatement ps = conn.prepareStatement("INSERT INTO TABLE_IMAGE_TEST (CODE, IMAGE) VALUES (?, ?)");
pstmt.setLong(1, 1L);
pstmt.setBytes(2, b);
pstmt.execute();
...
}
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