對(duì)于給定的字符串，如下所示：'Rob and Amber Mariano, Heather Robinson, Jane and John Smith, Kiwan and Nichols Brady John, Jimmy Nichols, Melanie Carbone, Jim Green and Nancy Brown, Todd and Sana Clegg with Tatiana Perkin'我想確定可能被稱為“John 和 Jane Doe”的夫婦或其他家庭成員，并排除“Jim Green 和 Nancy Brown”等案例。我只想識(shí)別以下內(nèi)容：Rob and Amber Mariano, Jane and John Smith, Kiwan and Nicholas Brady John, Todd and Sana Clegg下面正則表達(dá)式中的組似乎捕獲了我想要的大多數(shù)情況，但我在排除“Jim Green”時(shí)遇到了麻煩。我想提出的條件是第一個(gè)單詞是一個(gè)名稱，但它要么位于字符串的開頭，要么前面只有空格和逗號(hào)。但由于某種原因，我的表達(dá)不起作用。我期望 ([^|,\s']?) 捕捉到這一點(diǎn)，但它似乎并沒有這樣做。([^|\,\s]?)([A-Z][a-zA-Z]+)(\s*and\s*)([A-Z][a-zA-Z]+)(\s[A-Z][a-zA-Z]+)(\s[A-Z][a-zA-Z]+)?
3 回答
慕尼黑5688855
TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超2個(gè)贊
讓我們將答案分解為兩個(gè)簡(jiǎn)單的步驟。
將整個(gè)字符串轉(zhuǎn)換為一組情侶姓名。
獲取所有與所請(qǐng)求的模式匹配的對(duì)。
我們對(duì)遵循以下模式的情侶名字感興趣：
<Name1> and <Name2> <Last-name> <May-or-may-not-be-words-separated-by-spaces>.
<Name1> and <Name2> <Last-name>但我們只對(duì)每個(gè)匹配字符串的部分感興趣?，F(xiàn)在我們已經(jīng)定義了我們想要做什么，下面是相同的代碼。
import re
testStr = """Rob and Amber Mariano, Heather Robinson,
Jane and John Smith, Kiwan and Nichols Brady John,
Jimmy Nichols, Melanie Carbone, Jim Green and Nancy Brown,
Todd and Sana Clegg with Tatiana Perkin
"""
# Pattern definition for the match
regExpr = re.compile("^(\w+\sand\s\w+\s\w+)(\s\w)*")
# Remove whitespaces introduced at the beginning due to splitting
coupleList = [s.strip() for s in testStr.split(',')]
# Find all strings that have a matching string, for rest match() returns None
matchedList = [regExpr.match(s) for s in coupleList]
# Select first group which extracts the necessary pattern from every matched string
result = [s.group(1) for s in matchedList if s is not None ]
慕婉清6462132
TA貢獻(xiàn)1804條經(jīng)驗(yàn) 獲得超2個(gè)贊
有點(diǎn)晚了，但可能是最簡(jiǎn)單的正則表達(dá)式
import re
regex = r"(?:, |^)(\w+\sand\s\w+\s\w+)"
test_str = "Rob and Amber Mariano, Heather Robinson, Jane and John Smith, Kiwan and Nichols Brady, John, Jimmy Nichols, Melanie Carbone, Jim Green and Nancy Brown, Todd and Sana Clegg with Tatiana Perkin"
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print (match.group(groupNum))
輸出：
Rob and Amber Mariano
Jane and John Smith
Kiwan and Nichols Brady
Todd and Sana Clegg
皈依舞
TA貢獻(xiàn)1851條經(jīng)驗(yàn) 獲得超3個(gè)贊
試試這個(gè)...按預(yù)期完美工作
(,\s|^)([A-Z][a-z]+\sand\s[A-Z][a-z]+(\s[A-Z][a-z]+)+)
測(cè)試腳本：
import re
a=re.findall("(,\s|^)([A-Z][a-z]+\sand\s[A-Z][a-z]+(\s[A-Z][a-z]+)+)","Rob and Amber Mariano, Heather Robinson, Jane and John Smith, Kiwan and Nichols Brady John, Jimmy Nichols, Melanie Carbone, Jim Green and Nancy Brown, Todd and Sana Clegg with Tatiana Perkin")
print(a)
回復(fù)：
[('', 'Rob and Amber Mariano', ' Mariano'), (', ', 'Jane and John Smith', ' Smith'), (', ', 'Kiwan and Nichols Brady John', ' John'), (', ', 'Todd and Sana Clegg', ' Clegg')]
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