我正在解決一個(gè)家庭作業(yè)問(wèn)題，要求在同一行上打印第 N 個(gè)字符和第 N 個(gè)單詞，不帶空格。如果第 N 個(gè)單詞太短并且沒(méi)有第 N 個(gè)字符，則程序?qū)⒋蛴≡搯卧~的最后一個(gè)字符。如果用戶輸入空詞（簡(jiǎn)單地按下），則該詞將被忽略。（我們還沒(méi)有學(xué)習(xí)方法，所以我不應(yīng)該使用它們）請(qǐng)參閱下面的代碼，我不確定如何讓我的代碼打印該單詞的最后一個(gè)字符（如果它沒(méi)有第 N 個(gè)字符）。import java.util.Scanner;public class Words { public static void main(String[] args) { final int N=5; Scanner input = new Scanner(System.in); System.out.print("Enter a line of words seperated by spaces "); String userInput = input.nextLine(); String[] words = userInput.split(" "); String nthWord = words[N]; for(int i = 0; i < nthWord.length();i++) { if(nthWord.length()>=N) { char nthChar = nthWord.charAt(N); System.out.print("The " + N + "th word in the line entered is " + nthWord + "The " + N + "th charecter in the word is " + nthChar); } if(nthWord.length()<N) { char nthChar2 = nthWord.charAt(nthWord.length()-1); System.out.print("The " + N + "th word in the line entered is " + nthWord + "The " + N + "th charecter in the word is " + nthChar2); } input.close(); }}}當(dāng)我運(yùn)行這個(gè)時(shí)，我收到一個(gè)錯(cuò)誤：Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 5 at java.base/java.lang.StringLatin1.charAt(StringLatin1.java:47) at java.base/java.lang.String.charAt(String.java:702) at Words.main(Words.java:24)我希望在同一行看到第 N 個(gè)單詞和第 N 個(gè)字符
1 回答
胡子哥哥
TA貢獻(xiàn)1825條經(jīng)驗(yàn) 獲得超6個(gè)贊
用戶輸入也可以包含少于 N 個(gè)單詞，對(duì)嗎？首先檢查應(yīng)該是這樣。
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a line of words seperated by spaces ");
String userInput = input.nextLine();
String[] words = userInput.split(" ");
int n = words.length();
System.out.print("Enter lookup word - N");
int askedFor = input.nextInt();
if (askedFor > n) {
//your logic for this condition
return;
}
String nthWord = words[askedFor-1];
if (nthWord.length() < askedFor) print(nthWord.charAt(nthWord.length()-1));
else print(nthWord.charAt(askedFor-1));
input.close();
}
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