我正在嘗試在python中創(chuàng)建一個函數(shù)，將一個字符串拆分為兩個字符串，其中第一個字符串包含所有小寫字母+一些其他特殊字符，第二個字符串包含所有大寫字母+特殊字符。重點(diǎn)是能夠輸入：>>> first_message,second_message=string_split("SomEChaRacTers")>>> print(first_message, second_message)打印結(jié)果。這就是我現(xiàn)在所擁有的：def string_split(string): first_message_signs = "_." second_message_signs = " |" one = "" two = "" if len(string) == 0: return string if string[0].islower() or string[0] in first_message_signs: one += string[0] + string_split(string[1:]) return one elif string[0].isupper() or string[0] in second_message_signs: two += string[0] + string_split(string[1:]) return two else: return string_split(string[1:])在提示中進(jìn)行第一次調(diào)用時出現(xiàn)此錯誤： Traceback (most最近的調(diào)用最后): File "", line 1, in ValueError: Too much values to unpack (expected 2)當(dāng)我嘗試僅使用 message_one 時，我得到一個字符串中的所有字符。我應(yīng)該怎么辦？
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TA貢獻(xiàn)1796條經(jīng)驗(yàn) 獲得超7個贊
你的第一行
first_message,second_message=string_split("SomEChaRacTers")
期望string_split返回兩個值。然而，你的函數(shù)只返回一個。
你想要的是
def string_split(string):
first_message_signs = "_."
second_message_signs = " |"
one = ""
two = ""
if len(string) == 0:
return one, two
if string[0].islower() or string[0] in first_message_signs:
one += string[0]
elif string[0].isupper() or string[0] in second_message_signs:
two += string[0]
ret1, ret2 = string_split(string[1:])
one += ret1
two += ret2
return one, two
順便說一句，沒有令人信服的理由需要string_split遞歸。嘗試這個：
def string_split(string):
first_message_signs = "_."
second_message_signs = " |"
one = ''.join(c for c in string if c.islower() or c in first_message_signs)
two = ''.join(c for c in string if c.isupper() or c in second_message_signs)
return one, two
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