我正在開(kāi)發(fā)一個(gè)socks5代理服務(wù)器，現(xiàn)在我正在實(shí)現(xiàn)一種ICMP隧道方法，通過(guò)ICMP協(xié)議來(lái)傳輸SSH流量以繞過(guò)防火墻限制。這是我使用的開(kāi)源： https: //github.com/sanecz/pingtunnel def create(self): pack_str = "!BBHHH4sH" pack_args = [self.type, self.code, 0, self.id, self.sequence, socket.inet_aton(self.dest[0]), self.dest[1]] if self.length: pack_str += "{}s".format(self.length) pack_args.append(self.data) self.checksum = self._checksum(struct.pack(pack_str, *pack_args)) pack_args[2] = self.checksum return struct.pack(pack_str, *pack_args)具體來(lái)說(shuō)，這部分代碼給我?guī)?lái)了麻煩，我必須在 python3 中運(yùn)行此代碼才能匹配我的 Socks5 代理和反向端口轉(zhuǎn)發(fā)。self.checksum = self._checksum(struct.pack(pack_str, *pack_args))此行給我一個(gè)錯(cuò)誤“預(yù)期值不是 int”。也在這里： while count < countTo: thisVal = ord(packet[count+1]) * 256 + ord(packet[count]) csum = csum + thisVal csum = csum & 0xffffffff count = count + 2 if countTo < len(packet): csum = csum + ord(packet[len(packet) - 1]) csum = csum & 0xffffffffcsum = csum & 0xffffffff我刪除了行尾的 L。誰(shuí)能幫我移植這個(gè) ICMP.py 腳本并解釋一下？
1 回答
開(kāi)心每一天1111
TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超13個(gè)贊
嘿伙計(jì)們，經(jīng)過(guò)幾次嘗試，我終于自己解決了這個(gè)問(wèn)題！
這是編輯后的代碼：
#!/usr/bin/python3
import socket
import struct
ICMP_ECHO = 0
ICMP_ECHO_REQUEST = 8
class ICMPPacket(object):
def __init__(self, type, code, checksum, id,
sequence, data, source_ip, dest=(None, None)):
self.type, self.code, self.checksum = type, code, checksum
self.id, self.sequence, self.data = id, sequence, data
self.dest = dest
self.source_ip = source_ip
self.length = len(self.data)
def __repr__(self):
return "<ICMP packet: type = {s.type}, code = {s.code}, " \
"data length = {length}".format(s=self, length=len(self.data))
def __str__(self):
return "Type of message: {s.type}, Code {s.code},"\
"Checksum: {s.checksum}, ID: {s.id}, Sequence: {s.sequence}, " \
"Data: {s.data}, Data length: {length}".format(s=self, length=len(self.data))
def create(self):
#print("\nEntering CREATE!!\n\n")
pack_str = "!BBHHH4sH"
pack_args = [self.type, self.code, 0, self.id, self.sequence,
socket.inet_aton(self.dest[0]), self.dest[1]]
if self.length:
pack_str += "{}s".format(self.length)
#print("PACK STR: " + pack_str)
pack_args.append(self.data)
#print("Pack ARGS: \n", pack_args, "\n")
self.checksum = self._checksum(struct.pack(pack_str, *pack_args))
#print("CHECKSUM: ", self.checksum)
pack_args[2] = self.checksum
return struct.pack(pack_str, *pack_args)
@classmethod
def parse(cls, packet):
ip_pack_str = "BBHHHBBH4s4s"
icmp_pack_str = "!BBHHH4sH"
data = ""
ip_packet, icmp_packet = packet[:20], packet[20:] # split ip header
ip_packet = struct.unpack(ip_pack_str, ip_packet)
source_ip = ip_packet[8]
icmp_pack_len = struct.calcsize(icmp_pack_str)
packet_len = len(icmp_packet) - icmp_pack_len
if packet_len > 0:
icmp_data_str = "{}s".format(packet_len)
data = struct.unpack(icmp_data_str, icmp_packet[icmp_pack_len:])[0]
type, code, checksum, id, sequence, dest_ip, \
dest_port = struct.unpack(icmp_pack_str, icmp_packet[:icmp_pack_len])
return cls(type, code, checksum, id, sequence, data,
socket.inet_ntoa(source_ip),
(socket.inet_ntoa(dest_ip), dest_port))
@staticmethod
def _checksum(packet):
#print("Argument for checksum: !!\n",packet)
packet = packet.decode('ISO-8859-1') # edited to match python3
csum = 0
countTo = (len(packet) / 2) * 2
count = 0
while count < countTo:
thisVal = ord(packet[count+1]) * 256 + ord(packet[count])
#print("THISVAL: ", thisVal)
csum = csum + thisVal
csum = csum & 0xffffffff
count = count + 2
if countTo < len(packet):
csum = csum + ord(packet[len(packet) - 1])
csum = csum & 0xffffffff
csum = (csum >> 16) + (csum & 0xffff)
csum = csum + (csum >> 16)
checksum = ~csum
checksum = checksum & 0xffff
checksum = checksum >> 8 | (checksum << 8 & 0xff00)
return checksum
我對(duì)數(shù)據(jù)包進(jìn)行了重新編碼以匹配字節(jié)使用packet = packet.decode('ISO-8859-1')
為了匹配這一行thisVal = ord(packet[count+1]) * 256 + ord(packet[count])
因?yàn)樗枰粋€(gè)字符串，但它收到了一個(gè) INT。
因此將其解碼為字符串解決了這個(gè)問(wèn)題！
編輯：如果您對(duì)更好的編碼來(lái)處理數(shù)據(jù)包的二進(jìn)制數(shù)據(jù)有任何建議，請(qǐng)告訴我。
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