您好，我想按此順序列出該數(shù)組中所有可能情況的列表NUMBER LETTER NUMBER$a = array("0","1","2","3","4","5","6","7","8","9");$b = array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");$c = array("0","1","2","3","4","5","6","7","8","9");它將開始于0A0并以9Z9我嘗試過這樣的事情：foreach($a as $key1 => $first){ foreach($b as $key2 => $second){ foreach($c as $key3 => $third){ print_r($first[$key1].$second[$key2].$key3[$key3]); } }}但它不起作用，有什么幫助嗎？
2 回答
精慕HU
TA貢獻1845條經(jīng)驗 獲得超8個贊
您的數(shù)組引用是錯誤的。對于一個簡單的數(shù)組，當使用 foreach 時，$key幾乎無關(guān)緊要，因為該出現(xiàn)的值將在$firstor中$second......
foreach($a as $first){
foreach($b as $second){
foreach($c as $third){
echo $first . $second . $third . PHP_EOL;
}
}
}
如果您在瀏覽器上輸出此內(nèi)容，請更改PHP_EOL為'<br>'
米琪卡哇伊
TA貢獻1998條經(jīng)驗 獲得超6個贊
你差不多解決了。你不需要在這里使用密鑰。這是代碼
<?php
$a = array("0","1","2","3","4","5","6","7","8","9");
$b = array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");
$c = array("0","1","2","3","4","5","6","7","8","9");
foreach($a as $first){
foreach($b as $second){
foreach($c as $third){
echo ($first.$second.$third).PHP_EOL;
}
}
}
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