我是 Codeigniter 4 的新手，所以我問這個(gè)問題。事實(shí)上，我有兩個(gè)不同的型號(hào)。首先是tbl_user。其中有很多字段 tbl_user(id, name,duty_station,enlistment_date,dob) // 這里 id 是主鍵。其次是usermos。usermos 有四個(gè)字段 [id, user_id, mos_id, extra_mos_id] //這里id是主鍵，user_id是tbl_user的外鍵我已經(jīng)生成了 get_profile 的控制器...我想將usermos模型訪問到get_profile控制器中。以下是我的代碼標(biāo)頭<?php namespace App\Controllers;use CodeIgniter\RESTful\ResourceController;use App\Models\MosModel;use App\Models\Additional_mosModel;use App\Models\Api_auth_model;use App\Models\Api_Usermos_Model;控制器public function get_profile() { if (($this->request->getMethod() == 'post') && ($_SERVER['PHP_AUTH_USER'] == AUTHUSER_NAME) && ($_SERVER['PHP_AUTH_PW'] == AUTH_PASSWORD)) { if(!empty($this->request->getPost('id'))){ $user_api_mos_model = new Api_Usermos_Model(); $usermos = $this->user_api_mos_model->findAll(); print_r($usermos); exit; if($profile){ if($usermos){ } $selected_mos = $this->getMosFromID($usermos[0]['mos_id']); $selected_add_mos = $this->getAdd_MosFromID($usermos[0]['additional_mos_id']); $profile['badge'] = $this->getBadgeFromID($profile['badge_id']); // exit; return $this->respond([ "status" => "Success", "message" => "Profile found.", "Common" => ["Title" => "Load Profile API", 'version' => '1.0', 'Description' => 'Load Profile API', 'Method' => 'POST'], "Response" => ["Userdata" => $profile,"mos" => $selected_mos,"additonal_mos" => $selected_add_mos] ]); }else{ return $this->respond([ "status" => "Fail", "message" => "Profile Not found.", "Common" => ["Title" => "Load Profile API", 'version' => '1.0', 'Description' => 'Load Profile API', 'Method' => 'POST'], "Response" => ["Value" => 'Profile Not found.'] ]); } } } }感謝您寶貴的時(shí)間。
1 回答
qq_笑_17
TA貢獻(xiàn)1818條經(jīng)驗(yàn) 獲得超7個(gè)贊
只需在控制器頁面標(biāo)題部分的頂部定義模型的命名空間并在該控制器頁面中使用即可。例如：
<?php namespace App\Controllers;
use app\models\User;
use app\models\Usermos;
Class UserController extend controller {
public function actionProfile (){
$user = new User();
$user_mos = new Usermos();
}
}
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