我有一個包含以下元素的數(shù)組： $arr = ['N','P','K','Ca','Mg','S', 'Zn', 'B','Cu','Fe','Mn','Mo'];如何使用數(shù)組元素作為對象鍵以便僅獲取特定鍵的值：object(stdClass)[727]      public 'id' => int 1      public 'name' => string 'John Doe' (length=8)      public 'fname' => string 'HOUSE' (length=5)      public 'bname' => string 'BLOCK 9' (length=7)      public 'hectares' => float 7.2      public 'cname' => string 'Vitis vinifera' (length=14)      public 'delivery' => string '2210.0000' (length=9)      public 'view_application' => int 1      public 'view_schedule' => int 1      public 'edit_schedule' => int 0      public 'updated_at' => string '2020-07-17 20:03:51' (length=19)      public 'N' => string '4.9000' (length=6)      public 'P' => string '1.1000' (length=6)      public 'K' => string '6.0000' (length=6)      public 'Ca' => string '5.4000' (length=6)      public 'Mg' => string '0.8000' (length=6)      public 'S' => string '0.0000' (length=6)      public 'Zn' => string '0.0210' (length=6)      public 'B' => string '0.0071' (length=6)      public 'Cu' => string '0.0280' (length=6)      public 'Fe' => string '0.0420' (length=6)      public 'Mn' => string '0.0220' (length=6)      public 'Mo' => string '0.0000' (length=6)我嘗試使用這個：@for ($i = 0; $i < count($arr); $i++)   $object->$arr[$i];@endfor但這給出了一個錯誤Array to string conversion另一種方法是使用將對象轉換為數(shù)組$newarr = (array) $object; 然后使用迭代$object[''.arr[$i].''];但這對我來說不起作用，因為我已經(jīng)使用該對象完成了大部分項目。有沒有辦法使用數(shù)組元素作為對象鍵而不將對象轉換為數(shù)組？